All categories

3 years ago

Please answer correctly !!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!

Mathematics

2 answers:

melisa1 [442]3 years ago

6 0

Answer:

Step-by-step explanation:

So it’s pretty simple

A triangle’s hypotenuse (largest side of a triangle) had to be less than the two sides added together.

So if you add the 2 numbers and it’s greater than te hypotnuse, then its a possible triangle, if it’s less than the hypotnuse, there’s no way it can be a triangle.

So you add the first two since their the least and see if its less than and C is impossible becuase if you add the two, you’ll get 10+22=32 but the hypotnuse is 33 so it’s impossible.

The others are fine

ElenaW [278]3 years ago

3 0

The answer for this question is C
hope that helped

You might be interested in

Solve the equation. -5/4n =40

lina2011 [118]

I think the answer is a

8 0

4 years ago

I made a fort by two boxes. The first box is 4 meters long, 8 meters wide, and 8 meters high. The second box is 2 meters long, 7

ArbitrLikvidat [17]

Answer:

242 m³ of space is there in the fort.

Step-by-step explanation:

Given that,

The dimensions of first box is 4 meters long, 8 meters wide, and 8 meters high.

The dimensions of the second box is 2 meters long, 7 meters wide, and 1 meter high.

Space left = Volume of first box - volume of second box

= (4)(8)(8) - 2(7)(1)

= 242 m³

So, 242 m³ of space is there in the fort.

7 0

3 years ago

What is the value of the expression 3^2 +5^3-2^5? A. 14 B. 34 C. 102 D. 166

sleet_krkn [62]

C. 102 is the answer

8 0

3 years ago

Read 2 more answers

System of Equations Solve with Elimination Method

astra-53 [7]

For problem #1, multiply each variable in 4x-3y=1 by 2, and that should give you 8x+6y=2 which cancels out -8x+6y=-2. And for problem #2 you’ll need to find a numbers to multiply each equation so they cancel each other out

7 0

3 years ago

URGENT!!!! Please add workings out

Artist 52 [7]

Answer: 26.457 cm

Explanation:

First, the height of an equilateral triangle of side length a is:

$h = \frac{\sqrt{3} }{2}*a$

In this case, the side-length of the triangles is a = 10cm, then the height will be:

$h = \frac{\sqrt{3} }{2}*10cm = 8.66cm$

Now we can think on a triangle rectangle such that:

Point A and point F are vertexes of the triangle.

The line we want to find, the line from A to F, is the hypotenuse.

One cathetus is a the height of the triangle, that comes down from point A, the length of this cathetus is 8.66cm

The other cathetus is equal to half the side length of the triangles (5cm) plus the segments BD and DF (of 10cm each)

Then the length of this cathetus is 10cm + 10cm + 5cm = 25cm

Now, we can remember the Pythagorean theorem.

If H is the hypotenuse, and A and B are the catheti, then we have:

A^2 + B^2 = H^2

In this case, we know the length of both cathetus, and want to know the length of the hypotenuse, then:

(25cm)^2 + (8.66cm)^2 = H^2

√( (25cm)^2 + (8.66cm)^2) = H = 26.457 cm

Then the line from A to F is 26.457 cm

6 0

3 years ago