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3 years ago

~ PLEASE HELP ~ Determine the mKL in degrees. A) 108* B) 51* C) 58* D) 70*

Mathematics

2 answers:

Ludmilka [50]3 years ago

7 0

I think it’s D not sure tho

Masteriza [31]3 years ago

5 0

Answer:

Step-by-step explanation:

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The area of a square is 64 square feet. Each side of the square has a measure of feet.

Pie

Each side of the square is 16 ft

4 0

3 years ago

Help!! <br><br> I think I got these wrong, so please help!! Thank you!

Andrew [12]

Answer:

(x+3)(x+4)(x-4)

x+2 and x-3 are not factors but x-4 is

Step-by-step explanation:

let's factor it :)

x^3 + 3x^2 - 16x -48

first we will factor this:

x^3 + 3x^2

x^2(x + 3)

then factor the second part :

- 16x - 48

-16(x + 3)

so now,

x^2(x + 3) - 16(x + 3)

factor out x+3

(x+3)(x^2 - 16)

factor x^2 - 16

(x+3)(x+4)(x-4)

8 0

3 years ago

Find the value of x to the nearest degree.

Vinvika [58]

Answer: 77°

<u>Step-by-step explanation:</u>

In relation to ∠X, 3 is the adjacent side and 13 is the opposite side.

$tan\ \theta=\dfrac{opposite}{adjacent}\\\\tan\ x=\dfrac{13}{3}\\\\x = tan^{-1}\bigg(\dfrac{13}{3}\bigg)\\\\.\ =77$

3 0

4 years ago

John wants to measure the height of a tree. He walks exactly 100 feet from the base of the tree and looks up. The angle from the

kenny6666 [7]

Answer:

The height of the tree is $64.94\ ft$

Step-by-step explanation:

Let

y ----> the height of the tree

we know that

$tan(33\°)=y/100$ ----> the function tangent is equal to divide the opposite side angle of 33 degrees by the adjacent side angle of 33 degrees

Solve for y

$y=(100)tan(33\°)=64.94\ ft$

5 0

4 years ago

A recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distribute

Zina [86]

Answer:

Proportion of women having blood pressures between 88.1 and 89.4 is 3.99% or close to 4%.

Step-by-step explanation:

We are given that a recent study reported that diastolic blood pressures of adult women in the United States are approximately normally distributed with mean 80.3 and standard deviation 8.6.

Let X = blood pressures of adult women in the United States

So, X ~ N( $\mu=80.3,\sigma^{2} =8.6^{2}$ )

The z score probability distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean

$\sigma$ = population standard deviation

So, Probability that women have blood pressures between 88.1 and 89.4 is given by = P(88.1 < X < 89.4) = P(X < 89.4) - P(X $\leq$ 88.1)

P(X < 89.4) = P( $\frac{X-\mu}{\sigma}$ < $\frac{89.4-80.3}{8.6}$ ) = P(Z < 1.05) = 0.85314

P(X $\leq$ 88.1) = P( $\frac{X-\mu}{\sigma}$ $\leq$ $\frac{88.1-80.3}{8.6}$ ) = P(Z $\leq$ 0.89) = 0.81327

Therefore, P(88.1 < X < 89.4) = 0.85314 - 0.81327 = 0.0399 or approx 4%

Hence, proportion of women have blood pressures between 88.1 and 89.4 is 4%.

7 0

4 years ago