Answer:
4.24
Step-by-step explanation:
Use the distance formula ![d=\sqrt{(y_{2}-y_1)^{2} +(x_2-x_1)^2 }](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%28y_%7B2%7D-y_1%29%5E%7B2%7D%20%2B%28x_2-x_1%29%5E2%20%7D)
![d=\sqrt{(5-8)^2+(0-3)^2}\\\\d=\sqrt{(-3)^2+(-3)^2} \\\\d=\sqrt{9+9} \\\\d=\sqrt{18} \\\\\\d=3\sqrt{2}\\\\d=4.24](https://tex.z-dn.net/?f=d%3D%5Csqrt%7B%285-8%29%5E2%2B%280-3%29%5E2%7D%5C%5C%5C%5Cd%3D%5Csqrt%7B%28-3%29%5E2%2B%28-3%29%5E2%7D%20%5C%5C%5C%5Cd%3D%5Csqrt%7B9%2B9%7D%20%5C%5C%5C%5Cd%3D%5Csqrt%7B18%7D%20%5C%5C%5C%5C%5C%5Cd%3D3%5Csqrt%7B2%7D%5C%5C%5C%5Cd%3D4.24)
Total number of marbles = 5 + 8 + 7 = 20
Total number of non-red marbles = 5 + 7 = 12
P(not red) = 12/20 = 3/5
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Answer: 3/5
Answer:
<u>$15,000</u> is the amount to spend on marketing in the month of March.
Step-by-step explanation:
Given:
You have a monthly budget percentage of 5% for marketing.
Your projected sales for the month of March are $300,000.
Now, to find the amount spend on marketing:
Rate of marketing = 5%.
Projected sales for the month of March = $300,000.
Now, to get the amount spend on marketing in March:
<u><em>5% of $300,000.</em></u>
![=\frac{5}{100} \times 300,000](https://tex.z-dn.net/?f=%3D%5Cfrac%7B5%7D%7B100%7D%20%5Ctimes%20300%2C000)
![=0.05\times 300,000](https://tex.z-dn.net/?f=%3D0.05%5Ctimes%20300%2C000)
![=15,000.](https://tex.z-dn.net/?f=%3D15%2C000.)
Therefore, $15,000 is the amount to spend on marketing in the month of March.
Answer:
Because 4 is a perfect square
Step-by-step explanation:
When simplifying a radical, you have to look for perfect squares. 4 is a perfect square but x is not. Variables are only perfect squares if they have even numbered exponents so the x has to stay in the radical.
Answer:
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
![GH = 5](https://tex.z-dn.net/?f=GH%20%3D%205)
![EH = 13](https://tex.z-dn.net/?f=EH%20%3D%2013)
Step-by-step explanation:
Given
The attached figure
![EG = 12](https://tex.z-dn.net/?f=EG%20%3D%2012)
![FG = 5](https://tex.z-dn.net/?f=FG%20%3D%205)
Solving (a): EF
Since m is a perpendicular bisector, then <EGF and <EGH are right-angled.
So, EF will be calculated using Pythagoras theorem which states:
![EF^2 = EG^2 + FG^2](https://tex.z-dn.net/?f=EF%5E2%20%3D%20EG%5E2%20%2B%20FG%5E2)
![EF^2 = 12^2 + 5^2](https://tex.z-dn.net/?f=EF%5E2%20%3D%2012%5E2%20%2B%205%5E2)
![EF^2 = 144 + 25](https://tex.z-dn.net/?f=EF%5E2%20%3D%20144%20%2B%2025)
![EF^2 = 169](https://tex.z-dn.net/?f=EF%5E2%20%3D%20169)
Take the positive square roots of both sides
![EF = \sqrt{169](https://tex.z-dn.net/?f=EF%20%3D%20%5Csqrt%7B169)
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
Solving (b): GH
Since m is a perpendicular bisector, then GH = FG
![FG = 5](https://tex.z-dn.net/?f=FG%20%3D%205)
![GH = FG](https://tex.z-dn.net/?f=GH%20%3D%20FG)
![GH = 5](https://tex.z-dn.net/?f=GH%20%3D%205)
Solving (c): EH
Since m is a perpendicular bisector, then EH = EF
![EF = 13](https://tex.z-dn.net/?f=EF%20%3D%2013)
![EH = EF](https://tex.z-dn.net/?f=EH%20%3D%20EF)
![EH = 13](https://tex.z-dn.net/?f=EH%20%3D%2013)