All categories

3 years ago

Can someone help me pls ill give brainliest

Mathematics

2 answers:

tamaranim1 [39]3 years ago

8 0

Answer:

Step-by-step explanation:

Divide by 2.

example

8 divided by 2 is 4

I MIGHT BE Wrong but its the closest i can get'

Sergio [31]3 years ago

6 0

4, 5, 6, 7 are the answers

You might be interested in

?????????????!???????!???!?????

Archy [21]

Answer:

249.6

Step-by-step explanation

There are 4 identical equilateral triangle,

we can find the area of one and multiply by 4

area of triangle = $\frac{1}{2} *base*hight=\frac{1}{2}*12*10.4=62.4$

now 62.4*4 = 249.6

6 0

3 years ago

What is the most accurate representation of the area of a plot measuring 11.7cm by 15.4cm ?

Aleks04 [339]

Area=width*height
area=(11.7)*(15.4)
area=180.18cm^2

7 0

3 years ago

Find the directional derivative of f(x,y,z)=2z2x+y3f(x,y,z)=2z2x+y3 at the point (−1,4,3)(−1,4,3) in the direction of the vector

Feliz [49]

$f(x,y,z)=2z^2x+y^3$

$f$ has gradient

$\nabla f(x,y,z)=2z^2\,\vec\imath+3y^2\,\vec\jmath+4xz\,\vec k$

which at the point (-1, 4, 3) has a value of

$\nabla f(-1,4,3)=18\,\vec\imath+48\,\vec\jmath-12\,\vec k$

I'm not sure what the given direction vector is supposed to be, but my best guess is that it's intended to say $\vec u=15\,\vec\imath+25\,\vec\jmath$ , in which case we have

$\|\vec u\|=\sqrt{15^2+25^2}=5\sqrt{34}$

Then the derivative of $f$ at (-1, 4, 3) in the direction of $\vec u$ is

$D_{\vec u}f(-1,4,3)=\nabla f(-1,4,3)\cdot\dfrac{\vec u}{\|\vec u\|}=\boxed{\dfrac{294}{\sqrt{34}}}$

4 0

3 years ago

Find the area of the figure.

Hitman42 [59]

Answer:

Step-by-step explanation:

8x13=104-13=91 I have done this problem before on big ideas and it is either this or 87

5 0

4 years ago

What is a solution to (x + 6)(x + 2) = 60?

Elden [556K]

Answer:

Ox=4

Step-by-step explanation:

expand he equation

x²+8x-48=0

using substitution method (of the options)

4 substituted as X eliminates all an results to zero

16+32-48=0

please mark brainliest

4 0

3 years ago