Answer:
0.6b - 3c
Step-by-step explanation:
Multiply 0.2 and 3b
0.2 x 3b = 0.6b
Then multiply 0.2 and 15c
0.2 x 15c = 3c
We can't add these, 3c and 6b because they have different letters.
different letter vs. different letter =
don't add
different letter vs. normal number like 5 =
dont add
same letter vs. same letter =
add
normal number vs. normal number =
add
This all goes the same for dividing, subtracting, and multiplying
I hope this helped! :)
In order to use the remainder theorem, you need to have some idea what to divide by. The rational root theorem tells you rational roots will be from the list derived from the factors of the constant term, {±1, ±5}. When we compare coefficients of odd power terms to those of even power terms, we find their sums are equal, which means -1 is a root and (x +1) is a factor.
Dividing that from the cubic, we get a quotient of x² +6x +5 (and a remainder of zero). We recognize that 6 is the sum of the factors 1 and 5 of the constant term 5, so the factorization is
... = (x +1)(x +1)(x +5)
... = (x +1)²(x +5)
_____
The product of factors (x +a)(x +b) will be x² + (a+b)x + ab. That is, the factorization can be found by looking for factors of the constant term (ab) that add to give the coefficient of the linear term (a+b). The numbers found can be put directly into the binomial factors to make (x+a)(x+b).
When we have 1·5 = 5 and 1+5 = 6, we know the factorization of x²+6x+5 is (x+1)(x+5).
Answer:
<h2>
The eleventh term of the sequence is 64</h2>
Step-by-step explanation:
The sequence given is an arithmetic sequence
14, 19, 24, …………., 264
The nth term of an arithmetic sequence is given as;
Tn = a+(n-1)d where;
a is the first term = 14
d is the common difference = 19-14=24-19 = 5
n is the number of terms = 11(since we are to look for the eleventh term of the sequence)
substituting the given values in the formula given;
T11 = 14+(11-1)*5
T11 = 14+10(5)
T11 = 14+50
T11 = 64
The eleventh term of the sequence is 64
Answer:
You are <em>squaring x and -5 on the first equation</em>, and on the second equation you are <em>just squaring x and subtracting 5.</em>
Step-by-step explanation:
And since on the first equation x and -5 are in parenthesis that means that the square goes to both of them.
And the second one there is no parenthesis so the square only goes to the x.
I hope this helps you.
