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2 years ago

8

The cost of a sweater at a clothing store was $35. The sweater went on sale at a discount of 20% off the original price. What is

the sale price of the sweater?

2 answers:

belka [17]2 years ago

8 0

Answer:

$28

Step-by-step explanation:

First, we have to find 20% of 35.

We can do that by multiplying 0.20 by 35. (0.20 x 35)

After multiplying them, we get a product of $7.

Since the sweater went on sale and they took 20% off of the original price, we have to subtract $7 from the original price of $35. (35 - 7)

We can solve that to get us the discounted price of $28

(sorry if this is confusing but I hope it helped)

Tpy6a [65]2 years ago

6 0

The answer is 28$ :))

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a) The solution of this <em>ordinary</em> differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ .

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<h3>How to solve ordinary differential equations</h3>

a) In this case we need to separate each variable ( $y, t$ ) in each side of the identity:

$6\cdot \frac{dy}{dt} = y^{4}\cdot \sin^{4} t$ (1)

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Where $C$ is the integration constant.

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The solution of this <em>ordinary</em> differential equation is $y =\sqrt[3]{-\frac{2}{\frac{3\cdot t}{8}-\frac{\sin 2t}{4}+\frac{\sin 4t}{32}-2 } }$ . $\blacksquare$

b) In this case we need to solve a first order ordinary differential equation of the following form:

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Where:

$p(x)$ - Integrating factor
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The solution for (2) is presented below:

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$y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$

The <em>particular</em> solution of the <em>ordinary</em> differential equation is $y = \frac{x^{3}}{2}+x^{2}-\frac{5}{2}$ . $\blacksquare$

To learn more on ordinary differential equations, we kindly invite to check this verified question: brainly.com/question/25731911

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