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2 years ago

What is the value of q?

Mathematics

1 answer:

Free_Kalibri [48]2 years ago

5 0

Answer:

the value is 36

Step-by-step explanation: so you add

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The magnitude, M, of an earthquake is defined to be

lesantik [10]

Answer:

1.5

Step-by-step explanation:

The magnitude, M, of an earthquake is defined to be

M = log l/s

where I is the intensity of the earthquake and s is the intensity of a “standard” earthquake.

If an earthquake that is 35 times more intense than a standard earthquake, then l/s = 35. Replacing it in the equation:

M = log 35 = 1.5

5 0

2 years ago

Please help thank u

irina1246 [14]

Answer:

Step-by-step explanation:

The answer is c the third one

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2 years ago

You Exercise 24 hours each month for a year. How many hours did you exercise by the end of the year? with distribution?

laiz [17]

Each year is 12 months and each month we exercise for 24 hours so for one year we gonna exercise for : 12 × 24 = 288 hours :))

3 0

2 years ago

Help 32 points.......

german

Answer:

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

The Center for Medicare and Medical Services reported that there were 295,000 appeals for hospitalization and other Part A Medic

Ksivusya [100]

Answer:

(a) P (X = 0) = 0.006

(b) P (X = 1) = 0.0403

(d) P (X > 5) = 0.1664

Step-by-step explanation:

Let X = number of successful appeals.

The probability that an appeal is successful is, p = 0.40.

The sample size is, n = 10.

The random variable $X\sim Bin(n=10, p=0.40)$ .

The probability function of a Binomial distribution is:

$P(X=x)={n\choose x}p^{x}(1-p)^{n-x}$

(a)

The probability that none of the appeals is successful is:

$P(X=0)={10\choose 0}(0.40)^{0}(1-0.40)^{10-0}\\=1\times1\times0.0060466176\\=0.0060466176\\\approx0.006$

Thus, the probability that none of the appeals is successful is 0.006.

(b)

The probability that exactly one of the appeals will be successful is:

$P(X=1)={10\choose 1}(0.40)^{1}(1-0.40)^{10-1}\\=10\times0.40\times0.010077696\\=0.040310784\\\approx0.0403$

Thus, the probability that exactly one of the appeals will be successful is 0.0403.

(c)

The probability that at least two of the appeals will be successful is:

$P(X\geq 2)=1-P(X$

Thus, the probability that at least two of the appeals will be successful is 0.9537.

(d)

The probability that more than half of the appeals will be successful is:

$P(X> 5)=1-P(X\leq 5)\\=1-P(X=0)-P(X=1)-P(X=2)-P(X=3)-P(X=4)+P(X=5)\\=1-[{10\choose 0}(0.40)^{0}(1-0.40)^{10-0}]-[{10\choose 1}(0.40)^{1}(1-0.40)^{10-1}]\\-[{10\choose 2}(0.40)^{2}(1-0.40)^{10-2}]-[{10\choose 3}(0.40)^{3}(1-0.40)^{10-3}]\\-[{10\choose 4}(0.40)^{4}(1-0.40)^{10-4}]-[{10\choose 5}(0.40)^{5}(1-0.40)^{10-5}]\\=1 - 0.006-0.0403-0.1209-0.2150-0.2508-0.2006\\=0.1664$

Thus, the probability that more than half of the appeals will be successful is 0.1664.

7 0

2 years ago