Yay, derivitives
I'mma ignore that x is the shorter side because I don't know which one has to be shorter yet
we need to find the max area
but with 3 sides
area=LW
let's say the sides are z and y
zy=area
and the relatiionship between them is
hmm,
z+2y=1200
because one side has no fencing
so
z+2y=1200
solve for z
z=1200-2y
sub for z in other
(1200-2y)(y)=area
expand
1200y-2y²=area
take derivitive
1200-4y=dy/dx area
max is where dy/dx goes from positive to negative
solve for where dy/dx=0
1200-4y=0
1200=4y
300=y
at y<300, dy/dx<0
at y>300, dy/dx>0
so at y=300, that is the max
then
z=1200-2y
z=1200-2(300)
z=1200-600
z=600
so then
z=600
y=300
300<600
so the shorter side would be y
so then we see our choices and noticed that
erm
I think it is f(x)=1200x-2x²
takind the derivitive yeilds none of the others
so ya, you are right
Answer:
The Quadratic Formula is derived from the process of completing the square
Step-by-step explanation:
Focus of a parabola:
where vertex (h,k) p is the distance from vertex to focus
Answer:
length of C'B' is 4 units
length of CB is 8 units
the larger hexagon is twice as large as the smaller; scale is 2:1
Step-by-step explanation:
We will call small boxes x and big boxes y. This will mean that we have 2 different equations using the same two unknown weights. So, 2×y+8×x=106 and 5×y+2×x=103. Find how x and y relate to each other and apply it to one any of the equtions. 5y+2x=103 is the same as 5y=103-2x, and same as y=(103-2x)/5. Apply this relation we found to the other equation and we can find 2((103-2x)÷5)+8x=106, to (206-4x)÷5+8x=106, to (206+36x)÷5=106, to 206+36x=530, to 36x=324, to x=9. Apply again to any equation to find y, 5y+2(9)=103. 5y+18=103, to 5y=85, so y=17. Small boxes are 9kg and large boxes are 17kg
