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Leto [7]
3 years ago
15

Two ride-sharing companies, A and B, provide service for a certain city. A random sample of 52 trips made by Company A and a ran

dom sample of 52 trips made by Company B were selected, and the number of miles traveled for each trip was recorded. The difference between the sample means for the two companies
(A−B) was used to construct the 95 percent confidence interval (1.86,2.15).
Which of the following is a correct interpretation of the interval?
A. We are 95 percent confident that the difference in sample means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
B. We are 95 percent confident that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
C. The probability is 0.95 that the difference in sample means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
D. The probability is 0.95 that the difference in population means for miles traveled by the two companies is between 1.86 miles and 2.15 miles.
E. About 95 percent of the differences in miles traveled by the two companies are between 1.86 miles and 2.15 miles.
3. Two community service groups, J and K, each have less than 100 members. Members of both groups volunteer each month to participate in a community-wide recycling day. A study was conducted to investigate whether the mean number of days per year of participation was different for the two groups. A random sample of 45 members of group J and a random sample of 32 members of group K were selected. The number of recycling days each selected member participated in for the past 12 months was recorded, and the means for both groups were calculated. A two-sample t-test for a difference in means will be conducted. Which of the following conditions for inference have been met?

I. The data were collected using a random method.
II. Each sample size is less than 10 percent of the population size.
III. Eachsamplesizeislargeenoughtoassumenormalityofthesampling
distribution of the difference in sample means.
A. I only
B. II only
C. III only
D. I and III only E. I, II, and III
Mathematics
1 answer:
Bogdan [553]3 years ago
3 0
WTFFFFF this is hella long
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Step-by-step explanation:

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If vertex U is located at (-4, 5) and vertex V is located at (-6, 2), then vertex U′ is located at
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The vertex U' is located at (-4, -5)

<h3>How to determine the location of U'?</h3>

The vertices are given as:

U = (-4, 5)

V = (-6, 2)

The rule of transformation is given as:

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This is represented as:

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So, we have:

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1. Which expression is equivalent to 6(2y – 5)?
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Answer:

C. 12y - 30

Step-by-step explanation:

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12y - 30

7 0
3 years ago
A normally distributed population has a mean of 250 pounds
Dima020 [189]

Answer: 0.9746

Step-by-step explanation:

Given : A normally distributed population has a mean of 250 pounds and a standard deviation of 10 pounds.

i.e. \mu=250 \sigma=10

Sample size : n= 20

Let \overline{x} sample mean values.

Then, the probability that this sample will have a mean value between 245  and 255 be

P(245

Hence , the probability that this sample will have a mean value between 245  and 255 is 0.9746 .

6 0
3 years ago
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