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matrenka [14]
3 years ago
9

Which value does not represent the probability of an event? Which value does not represent the probability of an event? Group of

answer choices 0.0 0.5 1.0 2.0
Mathematics
1 answer:
VladimirAG [237]3 years ago
6 0
Home Access Center allows parents and students to view student registration, scheduling, attendance, assignment, and grade information. Home Access Center is ..
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Please help: If the area of a rectangular picture of a stamp is 81 times greater than the actual stamp's area, and the stamp has
ololo11 [35]

Answer:

12 inches.

Step-by-step explanation:

We know that the length of the stamp is 4/3 inches.

Let the width be x inches.

Then the area of the actual stamp is:

\frac{4}{3}x\text{ inches}^2

We know that the rectangular picture of the stamp is 81 times greater than the actual stamp’s area. Therefore, the area of the picture is 81 times the above. So:

81(\frac{4}{3}x)\text{ inches}^2

So, the area of the rectangular picture is the area of the actual stamp multiplied by a scale factor k.

When we use the scale factor to scale area, we need to square it. Hence, the area of the actual stamp times the scale factor squared is equal to the area of the rectangular picture. Therefore:

\frac{4}{3}x(k^2)=81(\frac{4}{3}x)

Let’s solve for the scale factor. Divide both sides by 4/3(x). Hence:

k^2=81

Take the square root of both sides:

k=9

So, the scale factor from the actual stamp to the picture is 9.

So, the actual stamp has a length of 4/3.

Then ThThe length of the stamp’s picture will be:

\frac{4}{3}k

Substitute 9 in for k to get:

=\frac{4}{3}(9)=12

So, the length of the stamp’s picture is 12 inches.

8 0
3 years ago
PLEASE HELP!! solve |2x-2| ≥6.
Anastaziya [24]
<h3>Answer:</h3>

x ≤ -2    OR  x ≥ 4

__________________________________________________________

<h3>Step-by-step explanation:</h3>

<u>We are given the inequality:</u>

|2x - 2| ≥ 6

Getting rid of the Modulus:

Since 2x-2 is in modulus:

|2x-2| =  -(2x-2)    OR   2x-2

<em>(since the modulus of both these values is 2x-2)</em>

Hence, our inequality can be written in 2 different ways:

  1. 2x-2 ≥ 6                              <em>(if 2x-2 ≥ 1)</em>
  2. -(2x - 2) ≥ 6                         <em>(if 2x-2 < 0)</em>

__________________________________________________________

<u>Solving these 2 inequalities:</u>

Solving inequality 1:

2x - 2 ≥ 6                

2x ≥ 8                     [<em>adding 2 on both sides]</em>

x ≥ 4                       [<em>dividing both the sides by 2]</em>

This is the solution of the inequality if: 2x-2 ≥ 0

Solving Inequality 2:

-(2x-2) ≥ 6

<em>It can be rewritten as:</em>

2 - 2x ≥ 6                

2 ≥ 6 + 2x                [<em>adding 2x on both the sides]</em>  

-4 ≥ 2x                     [<em>Subtracting 6 from both sides]</em>

x ≤ -2                       [<em>Dividing both sides by 2]</em>

This is the solution of the given inequality if: 2x-2 < 0

__________________________________________________________

<u>Solution of the given Inequality:</u>

Therefore, the solution of the given inequality |2x-2| ≥ 6 are:

x ≥ 4   <em>(if 2x-2 </em>≥ 0)

x ≤ -2  <em>(if 2x-2 < 0)</em>

Hence, option C is correct!

6 0
3 years ago
GEOMETRY HELP? Circle O is shown below. What is the measure of BAC?
Firdavs [7]
B. You need to add 73 and 73
4 0
3 years ago
Read 2 more answers
-15 = x/-0.5 solve for x
fomenos

Answer:

\boxed{\bold{x=7.5}}

Step By Step Explanation:

➤ Switch Sides

\bold{\frac{x}{-0.5}=-15}

➤ Multiply Both Sides By -0.5

\bold{\frac{x\left(-0.5\right)}{-0.5}=\left(-15\right)\left(-0.5\right)}

➤ Simplify

\bold{x=7.5}

- Mordancy

6 0
4 years ago
Read 2 more answers
A combination lock requires a user to select three numbers to unlock it, where all three numbers are between 1 to 30, inclusive.
Anarel [89]

you can repeat numbers

3 numbers between 1 to 30 including 1 and 30

that means (30-1)+1=30 numbers

3 slots that can be repeated

so there are 30^3=27000 combinations


in 100 attempts, hmm

that is a 100/27000=1/270 chance or about 0.37% chance

7 0
3 years ago
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