Let's call the number "n"
if we write in an equation what you said it's like this:
n*2+4-n-3=n+1.
first i will move all the "n"s to the left and all the numbers to the right
n*2-n-n=1+3-4
which is....
0=0
this means that for EVERY number, if you double it, add four, subtract three, you will get this number plus one. <span />
Answer:
The answer to your question is (1, -2)
Step-by-step explanation:
See the graph below, in the graph, the solution is circled (1, -2). The solution is the point where the lines cross.
To check the answer, let's solve the system using algebra.
y = 2x - 4
y = 1 - 3x
2x - 4 = 1 - 3x
2x + 3x = 1 + 4
5x = 5
x = 5/5
x = 1
Find y by substitution
y = 2(1) - 4
y = 2 - 4
y = -2
Solution
(1, -2)
Can you help me please I need help with a couple of questions
Given:
quarterly deposits of 2,000
8 percent compounded quarterly ⇒ 2% per quarter
4 quarters in 15 years = 60 quarters
Future Value = (1 + r) x P [{(1+r)^n - 1} / r]
FV = (1 + 0.02) x 2,000 [{(1 + 0.02)⁶⁰ - 1} / 0.02]
FV = 232, 665.14 Choice B.
