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maria [59]
4 years ago
15

Please help quick! Answer all three for 50 POINTS!!

Mathematics
1 answer:
mario62 [17]4 years ago
5 0

Answer:

8. B. obtuse, isosceles

9. B. 43 degrees

10. A. 14 degrees

Step-by-step explanation:

8. The triangle has two equal sides and its angles are above 90 degrees.

9. All triangle angles add up to 180 degrees

10. Same as above.

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Please evaluate this for me
dolphi86 [110]

so, 2 raised to what power would make 32?? it would be 5 because 2^5=32

2^1=1

2^2=4

2^3=16

2^5=32

7 0
3 years ago
Joe drove 100 miles from San Francisco to Gilroy and used 4 gallons of gas. How much gas should he expect to use for a 3000-mile
erma4kov [3.2K]
750 bc u dived 3000 by 4 bc 4 is per ever 100
3 0
3 years ago
Read 2 more answers
Find the sum of square root 5 and 2 square root 16 in simplest form. Also, determine whether the result is rational or irrationa
a_sh-v [17]

Answer:

sqrt(5) + 8

The result is irrational because the sqrt(5) is a non-repeating, non terminating decimal that cannot be written as a fraction.

<em>Brainliest, please!</em>

Step-by-step explanation:

sqrt(5) + 2sqrt(16)

sqrt(5) + 2(4)

sqrt(5) + 8

8 0
3 years ago
Please help me, I need an answer as soon as possible.
Lemur [1.5K]

Answer:

\huge\boxed{\sf x = \pm \sqrt{7} }

Step-by-step explanation:

<u>Given function:</u>

f(x)=x^2-7

<u>We can also write it as:</u>

y =x^2-7

x-intercept is the point where y = 0

Put y = 0 in the above equation

0=x^2-7\\\\Add \ 7 \ to \ both\ sides\\\\7 = x^2\\\\Take \ sqrt \ on \ both \ sides\\\\\pm \sqrt{7} =x\\\\x = \pm \sqrt{7} \\\\\rule[225]{225}{2}

3 0
3 years ago
Jane cloaked in to world on Tuesday at 7:30 am and went to her lunch at 11:30 am. She returned from her lunch break at 12:30 pm
shutvik [7]

Answer:

7 hours 30 minutes

Step-by-step explanation:

Jane clocks into work at 7:30 and goes to lunch at 11:30. (4 hours)

4 hours so far.

takes 1 hour break and returns for 12:30.

She finishes at 4. Time from 12:30 to 4 is (3h30)

3h30 + 4 = 7h30m

Check yourself ^

8 0
3 years ago
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