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pishuonlain [190]
3 years ago
15

Which substance is a binary compound?

Chemistry
2 answers:
PIT_PIT [208]3 years ago
6 0

Answer: The correct answer (C).

Explanation:

Binary compounds: These are the type of chemical compounds which are composed of two different elements. They cannot be further simplified by any  chemical methods.

Here , in given option carbon dioxide is a binary compound made up of carbon and oxygen element.

Where as barium and beryllium are pure elements and calcium hydroxide is compound made up of three elements :  calcium, hydrogen and oxygen.

So, the correct answer (C).

AysviL [449]3 years ago
4 0
A binary compound is a compound that contain two different chemical elements in it. These compounds may be molecular or may also exist in other forms such as solid. In this case Barium and Beryllium are not binary compounds since they are independent elements, Calcium hydroxide is also not a binary compound since it has more than two chemical elements. Therefore,carbon dioxide is the binary compound since it contains two chemical elements ( carbon and oxygen)
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Answer:

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Explanation:

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A solution contains 0.60 mg/ml mn2+. what minimum mass of kio4 must me added to 5.00 ml of the solution in order to completely o
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The given solution of Mn²⁺ is 0.60 mg/mL.
Hence mass of Mn²⁺ in 5 mL of solution = 0.60 mg/mL x 5 mL = 3 mg

Molar mass of Mn = 54.9 g/mol
Hence, moles of Mn²⁺ = 3 x 10⁻³ g / 54.9 g/mol = 5.46 x 10⁻⁵ mol

The balanced equation for the reaction is,
2Mn²⁺ + 5KIO₄ + 3H₂O → 2MnO₄⁻ + 5KIO₃ + 6H⁺

The stoichiometric ratio between Mn²⁺ and KIO₄ is 2 : 5

Hence, moles of KIO₄ reacted = 5.46 x 10⁻⁵ mol x (5 / 2)
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Molar mass of KIO₄ = 230 g/mol

Hence needed mass of KIO₄ = 13.65 x 10⁻⁵ mol x 230 g/mol
                                               = 0.031395 g
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A student is asked to seperate two liquids. Liquid A boils at 100°c and liquid B boils at 65°c. The student sets up a fractional
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One beaker contains 19.93 mL, another contains 14.0 mL and a third contains 10.6 mL. What is the total volume of the three beake
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\large \boxed{\text{44.5 mL}}

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When adding or subtracting values, you must round your answer to the same "place" as the measurement with its last significant figure furthest to the left.  

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\begin{array}{r|r}19.9& \text{3 mL}\\14.0&\text{mL}\\10.6&\text{mL} \\\mathbf{44.5} &\textbf{3 mL}\\\end{array}

The measurements of 14.0 and 10.6 have one digit after the decimal point, so you round the sum to have only one digit to the right of the decimal.

The number to be dropped (3) is less than 5, so you drop it.

\text{The total volume of the three beakers is $\large \boxed{\textbf{44.5 mL}}$}

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