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pishuonlain [190]
4 years ago
15

Which substance is a binary compound?

Chemistry
2 answers:
PIT_PIT [208]4 years ago
6 0

Answer: The correct answer (C).

Explanation:

Binary compounds: These are the type of chemical compounds which are composed of two different elements. They cannot be further simplified by any  chemical methods.

Here , in given option carbon dioxide is a binary compound made up of carbon and oxygen element.

Where as barium and beryllium are pure elements and calcium hydroxide is compound made up of three elements :  calcium, hydrogen and oxygen.

So, the correct answer (C).

AysviL [449]4 years ago
4 0
A binary compound is a compound that contain two different chemical elements in it. These compounds may be molecular or may also exist in other forms such as solid. In this case Barium and Beryllium are not binary compounds since they are independent elements, Calcium hydroxide is also not a binary compound since it has more than two chemical elements. Therefore,carbon dioxide is the binary compound since it contains two chemical elements ( carbon and oxygen)
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2 H2S(g) ⇄ 2 H2(g) + S2(g) Kc = 9.3× 10-8 at 400ºC 0.47 moles of H2S are placed in a 3.0 L container and the system is allowed t
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<u>Answer:</u> The concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

<u>Explanation:</u>

We are given:

Initial moles of hydrogen sulfide gas = 0.47 moles

Volume of the container = 3.0 L

The molarity of solution is calculated by using the equation:

\text{Molarity}=\frac{\text{Moles of solute}}{\text{Volume of the solution}}

So, \text{Initial molarity of hydrogen sulfide gas}=\frac{0.47}{3}=0.1567M

The given chemical equation follows:

                          2H_2S(g)\rightleftharpoons 2H_2(g)+S_2(g)

<u>Initial:</u>                  0.1567

<u>At eqllm:</u>           0.1567-2x       2x         x

The expression of K_c for above equation follows:

K_c=\frac{[H_2]^2[S_2]}{[H_2S]^2}

We are given:

K_c=9.3\times 10^{-8}

Putting values in above equation, we get:

9.3\times 10^{-8}=\frac{(2x)^2\times x}{(0.1567-2x)^2}\\\\x=8.24\times 10^{-4}

So, equilibrium concentration of hydrogen gas = 2x=(2\times 8.24\times 10^{-4})=1.648\times 10^{-3}M

Hence, the concentration of hydrogen gas at equilibrium is 1.648\times 10^{-3}M

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Answer:

https://www.wolframalpha.com/

Explanation:

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