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saw5 [17]
3 years ago
6

Find two consecutive positive integers such that the sum of their squares is 421

Mathematics
1 answer:
alexandr402 [8]3 years ago
6 0
14 and 15
14^2 = 196
15^2 = 225
225+196 = 421
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Please help!
saw5 [17]
Quick Answer: 36 + 10h
Long explanation below
Alright, as we can see in the question, it's asking you to use the commutative property (of addition, 'cause that's the operation being used).
We know that this property states that you can move terms around in an addition problem and still get the same result.

So since there are only two terms in the expression given, you can just switch the terms around, giving you..
36 + 10h.
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