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3 years ago

6 Which expression below has a coefficient of 3?

Mathematics

2 answers:

geniusboy [140]3 years ago

5 0

option c is the correct cofficient of 3

kap26 [50]3 years ago

5 0

Option c is the correct answer choice

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If the area of a square is 32 ft2, how long is its diagonal?

Tema [17]

Diagonal = 8

D=diagonal

A=area

A=D^/2

32=D^/2

32/1 = D^/2

cross multiplication

32x2=D^x1

64=D^

8 =D

7 0

3 years ago

A map has the scale 0.5 of an inch equals 180 miles. The distance from Springfield to Glenview is 4 inches. How many actual mile

Amiraneli [1.4K]

180 multiplied by 4 is the answer.

6 0

3 years ago

I got c but not sure for both

belka [17]

Answer:

c588544gvfdf7544rv

Step-by-step explanation:

fd55

8 0

2 years ago

Read 2 more answers

Multiply............

ZanzabumX [31]

Hey there!

In order to multiply these polynomials together, you will take both terms of the first polynomial and multiply them by each term in the second polynomial. You can then combine any like terms to get your final answer.

(2x² – 5x)(4x² – 12x + 10)

2x² × 4x² = 8x⁴
2x² × –12x = –24x³
2x² × 10 = 20x²

–5x × 4x² = –20x³
–5x × –12x = 60x²
–5x × 10 = –50x

Write all of these terms together. You can rearrange the similar ones to be next to each other.

8x⁴ – 24x³ – 20x³ + 20x² + 60x² – 50x

Just add or subtract the terms to simplify, if they can be.

8x⁴ – 44x³ + 80x² – 50x

(8x⁴ – 44x³ + 80x² – 50x) will be your final answer.

Hope this helped you out! :-)

8 0

3 years ago

Read 2 more answers

State the equation of the line that is perpendicular to 4x-3y=10 through the point (-2,4)

Lynna [10]

The equation of the line that is perpendicular to 4x - 3y = 10 through the point (-2,4) is $y-4=\frac{-3}{4}(x+2)$

Solution:

Given, line equation is 4x – 3y = 10

We have to find a line that is perpendicular to 4x – 3y = 10 and passing through (-2, 4)

Now, let us find the slope of the given line,

$\text { Slope of a line }=\frac{-\mathrm{x} \text { coefficient }}{\mathrm{y} \text { coefficient }}=\frac{-4}{-3}=\frac{4}{3}$

We know that, slope of a line $\times$ slope of perpendicular line = -1

$\begin{array}{l}{\text { Then, } \frac{4}{3} \times \text { slope of perpendicular line }=-1} \\\\ {\rightarrow \text { slope of perpendicular line }=-1 \times \frac{3}{4}=-\frac{3}{4}}\end{array}$

Now, slope of our required line = $\frac{-3}{4}$ and it passes through (-2, 4)

The point slope form is given as:

$\begin{array}{l}{y-y_{1}=m\left(x-x_{1}\right) \text { where } m \text { is slope and }\left(x_{1}, y_{1}\right) \text { is point on the line. }} \\\\ {\text { Here in our problem, } m=-\frac{3}{4}, \text { and }\left(x_{1}, y_{1}\right)=(-2,4)} \\\\ {\text { Then, line equation } \rightarrow y-4=-\frac{3}{4}(x-(-2))}\end{array}$

$y-4=\frac{-3}{4}(x+2)$

Hence the equation of line is found out

6 0

3 years ago