Answer:
50% wild type and 50% black i.e. 1:1 phenotypic ratio
Explanation:
Given, b+ = wild type allele
b = recessive allele
b+b+ = dominant wild type
b+b = heterozygous wild type
bb = recessive black
First cross: female b+b (wild type) X male bb (black) = bb, bb, b+b, b+b
Since bb and b+b are in 1:1 phenotypic ratio, 52 black and 58 wild type progeny are produced.
From this progeny second cross occurs between:
female bb (black) X male (wild type) b+b = bb, bb, b+b, b+b
Again the same 1:1 phenotypic ratio is obtained. Half of the progeny will be be black (bb), other half will be wild type (b+b).
I would go with mathmatical formula because of physics and what not but I'm not completely sure so if you have a different possible answer you think would be better, go with that :)
A chromosome deletion occurs when a chromosomal fragment is lost. Thus the chromosome is missing some genes. One example of this in humans is know as cry of the cat. It occurs from a deletion on a chromosome number 5. A child that is born has a mental disability a small head with unusual facial features and cries like the sound of a distressed cat. The children rarely live into adulthood.
I hope this help
<span>The answer is A -The red geranium is heterozygous for red flowers (Rr).
We know that the red flower, to be red needs to have at least a dominant allele, so it could be either Rr or RR.
Let's try both scenarios.
If the white</span><span> geranium (rr) is being crossed with RR, all the offspring would be red with genotype: Rr.
On the other hand, if the flower is Rr and it's being crossed with rr, that would result in </span><span>half of the new generation plants having red flowers and the other half white flowers.</span>
<span>Rana sylvatica.
Hope this helps!
-Payshence xoxo</span>
