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3 years ago

5

0.5 ft of snow melts to 2inches of H2o. To how many inches will 4.5 ft of snow melt?

1 answer:

ladessa [460]3 years ago

5 0

Answer:

4.5 feet of snow = 27 inches H2o. Please read the explanation for better details

Step-by-step explanation:

if 0.5 feet of snow melts into 2 inches of water, then that means that 6 inches of snow melts into 2 inches of water. This means that for every 2 inches of snow you melt, it will become 1 inch of water. If 4.5 ft = 54 inches, you simply divide by 2, getting your answer of 27 inches of snow. Hope this helps! :)

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The mean per capita income is 20,90820,908 dollars per annum with a standard deviation of 407407 dollars per annum. What is the

LiRa [457]

Answer:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

So then the probability that the sample mean would differ from the true mean by less than 28 dollars from the sample of 55 is approximately 0.390

Step-by-step explanation:

We define the variable of interest as the per capita income and we know the following properties for this variable:

$\mu=20908$ and $\sigma=407$

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$P(20908-28$

We select a sample size of n=55 and we define the z score formula given by:

$z=\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}$

We can find the z score then for 20880 and 20936 and we got:

$z=\frac{20880-20908}{\frac{407}{\sqrt{55}}}= -0.51$

$z=\frac{20936-20908}{\frac{407}{\sqrt{55}}}= 0.51$

Then we can find the probability of interest with this difference:

$P(-0.51$

And using the normal standard distribution or excel we got:

$P(-0.51$

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Answer:

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Step-by-step explanation:

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chubhunter [2.5K]

Answer:

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