Answer:
There are about 5,357 bees in the hive
Step-by-step explanation:
Let
x -----> the number of bees that leave the hive in one minute
y -----> the approximate number of bees in a hive
we know that
The formula to calculate the approximate number of bees in a hive is equal to

For x=25
substitute


therefore
There are about 5,357 bees in the hive
Hey There!
Remember, first find the gcf of 4,3 in this problem it is 12.
Steps to solve
1.6

- 3

2.6

- 3

= 2

So, The answer is <span>2

</span>
Hope This Helps :)
40(12.62) + 7(12.62(1.5)) = 504.80 + 7(18.93) = 504.80 + 132.51 =
637.31 <===
Answer: Bears: 1.80 Saints: 1.40
Step-by-step explanation: Hope this helps!!
Answer:
2.28% probability that a person selected at random will have an IQ of 110 or higher
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

What is the probability that a person selected at random will have an IQ of 110 or higher?
This is 1 subtracted by the pvalue of Z when X = 110. So



has a pvalue of 0.0228
2.28% probability that a person selected at random will have an IQ of 110 or higher