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Lena [83]
4 years ago
9

) Kayden is given this question

Mathematics
2 answers:
jonny [76]4 years ago
6 0

Answer:

Kayden is wrong for multiple reasons: wrong answer and wrong form. The correct answer is 3.6 x 10^7

Step-by-step explanation:

12 x 3 = 36

6 zeros + 1 for moving the decimal on 36 = 7

3.6 x 10^7

jarptica [38.1K]4 years ago
5 0

Answer:

36,000,000

Step-by-step explanation:

12000 x 3000 = 36,000,000

Kayden's previous answer is wrong and also written in scientific notation. The above answer written in scientific notation is 3.6 x 10^7.

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If 64 feet of rope weighs 20 pounds how much will 80 feet of the same type of rope weigh?​
worty [1.4K]

Answer:

25 pounds, hope its right

Step-by-step explanation

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3 years ago
A small fountain holds 38 gallons of water in 4 equal-sized sections.
NemiM [27]
A 38/4
B 9 2/4
C 9 1/2

5 0
3 years ago
Solve:<br>√100 - √1 + √36​
Vladimir79 [104]

Hi there!

√100=10

√1=1

√36=6

10-1+6

9+6

15

Hope this helps

ANSWERED:\\GraceRosalia

7 0
3 years ago
Read 2 more answers
Rodell wants to find the favorite gaming app among the students at his school. He decides to poll the thirty students
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Step-by-step explanation:

Rudra should have collected the students equally both from football and pump basketball

3 0
4 years ago
Prove diagonals of a rhombus are perpendicular
Lisa [10]

Answer:

A rhombus is a parallelogram with four congruent sides.

So, all sides of rhombus ABCD are congruent.

i.e, \overline{JM} \cong \overline{JK} \cong \overline{KL}\cong \overline{LM}

Also, we know that the diagonals of a parallelogram bisect each other.  

Since a rhombus is a parallelogram.

By property of rhombus , if point N is the intersection of the diagonals as shown in the figure, then

\overline{MN} \cong \overline{NK}         .....[1]

\overline{JN} \cong \overline{NL}

In ΔJNM and ΔJNK

\overline{MN} \cong \overline{NK}     [side]    [by (1)]

\overline{JM} \cong \overline{JK}     [side]          [Given]

By reflexive property states that a segment is congruent to itself:

\overline{JN} \cong \overline{JN}   [Side]                 [Reflexive Property]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

then by SSS congruence,

\triangle JNM \cong \triangle JNK

By CPCT [Corresponding Part of congruent triangles are congruent]

Since, JNM and JNK are corresponding angles therefore,

\angle JNM \cong JNK

Linear pair theorem states that two angles that form a linear pair are supplementary.

By linear pair theorem, JNM and JNK are supplementary

this mean:

m\angle JNM +m\angle JNK =180^{\circ}

Since, the angles are congruent i.e, \angle JNM \cong JNK

so;

m\angle JNK +m\angle JNK =180^{\circ}

or

m\angle JNK +m\angle JNK =180^{\circ}

2m\angle JNK=180^{\circ}

Simplify:

m\angle JNK =90^{\circ}

also; m\angle JNM =90^{\circ}

therefore, the diagonals of JKLM are perpendicular to each other i,e \overline{JL} \perp \overline{MK}


4 0
3 years ago
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