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stiv31 [10]
3 years ago
14

£250 in the ratio 4 to 1

Mathematics
1 answer:
Andrej [43]3 years ago
4 0
In the event that you are asking to devide parts, we will use the equation   

·X+X²=Y

We Plug in our parts

·4x+1x=5x(Y)

We then substitute

·4x+1x=250(5x)

Then we devide Y(250) by the number of parts total.

·5 parts total.

·250/5=50

·1 part=50.

Next we substitute.

·200(4)+50(1)=250(5)

-In conclusion your answer is 50£:200<span>£, i hope this is the answer you are looking for, feel free to post your questions here in brainly in the future.</span>
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Take wholesale cost and multiply it by 95%, then add to the original value

another way, just multiply by 1.95

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Step-by-step explanation:

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Explain 15 is not a prime factor
MissTica

<em>1</em><em>5</em><em> </em><em>is</em><em> </em><em>not</em><em> </em><em>a</em><em> </em><em>prime</em><em> </em><em>factor</em><em> </em><em>as</em><em> </em><em>it</em><em> </em><em>is</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>1</em><em>,</em><em>3</em><em>,</em><em>5</em><em> </em><em>and</em><em> </em><em>1</em><em>5</em><em>.</em>

<em>Additional</em><em> </em><em>information</em><em>:</em>

<em>Prime</em><em> </em><em>numbers</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>only</em><em> </em><em>be</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>itself</em><em> </em><em>.</em><em>for</em><em> </em><em>instance</em><em>:</em><em>1</em><em>,</em><em>2</em><em>,</em><em>3</em><em>,</em><em>5</em><em>,</em><em>7</em><em> </em><em>,</em><em>1</em><em>1</em><em>,</em><em>1</em><em>3</em><em> </em><em>etc</em><em>.</em>

<em>Composite</em><em> </em><em>number</em><em> </em><em>s</em><em> </em><em>are</em><em> </em><em>those</em><em> </em><em>numbers</em><em> </em><em>which</em><em> </em><em>can</em><em> </em><em>be</em><em> </em><em>also</em><em> </em><em>divided</em><em> </em><em>by</em><em> </em><em>other</em><em> </em><em>numbers</em><em>,</em><em>For</em><em> </em><em>instance</em><em>:</em><em> </em><em>4</em><em>,</em><em>6</em><em>,</em><em>8</em><em>,</em><em>1</em><em>0</em><em> </em><em>etc</em>

<em>Hope</em><em> </em><em>it </em><em>helps</em><em>.</em><em>.</em><em>.</em><em>.</em>

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Step-by-step explanation:

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