Question

Please answer and Explain

Answer 1

Answer:

$T_n = T_{n-1} + 11$

$T_1 = -8$

Step-by-step explanation:

Given

$-8, 3, 14, 25,...$

Required

The recursive function

Let the nth term of the sequence be $T_n$

The given sequence is an arithmetic sequence that has the following common difference (d)

$d = T_2 - T_1$

$d = 3--8$

$d =11$

So, the nth term is:

$T_n = T_{n-1} + d$

$T_n = T_{n-1} + 11$

Hence, the recursion is:

$T_n = T_{n-1} + 11$  where $T_1 = -8$