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andreev551 [17]
4 years ago
8

A newly isolated natural product was found to have the molecular formula C15H28O2. By hydrogenating a sample of the compound, it

was determined to possess one pi bond. How many rings are present in the compound?
Chemistry
1 answer:
sveticcg [70]4 years ago
3 0

Answer:

One ring is present.

Explanation:

The degree of unsaturation  or double bond equivalents(DBE) can be determined by using a formula. This formula gives us the number of rings and / pi bonds.

As mentioned in the problem the number of pi bond is one so if we calculate the DBE this will give us the number of rings by subtracting one from DBE.

DBE=C+1-\frac{H}{2}-\frac{X}{2}+\frac{N}{2}

Where

C = number of carbon atoms

X = number of halogens

N = number of nitrogen

H = number of hydrogen

DBE=15+1-(\frac{28}{2})-(0)+(0)

DBE=16-14=2

Thus the number of rings will be:

Rings=2-1=1

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Answer:

POINTS OF INTERSECTION ARE:

x = -1

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Coordinates :

Explanation:

Condition for intersecting lines

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here

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frac{-1}{6}\neq\frac{1}{1}\neq\frac{1}{1}

Calculation :

Here substitution method is used : Value of y from eq (1) is substitued in equation (2)

-x + y = 4

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6x + 4 + x = -3  ( from i)

7x = -3 - 4

7x = -7

x = frac{-7}{7}

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using equation(i)

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Check:

The values of x and y should satisfy equation (1) and (2)

for equation 1

-x+y =4

= -(-1) + 3

= 1 + 3

= 4

Hence coordinates satisfy equation 1

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