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3 years ago

What does the author list in the passage?

Chemistry

2 answers:

irina [24]3 years ago

3 0

Answer:

B --> Different types of electromagnetic radiation

Explanation:

Science tells us that light is the reason we are able to see objects. Without light, we wouldn't be able to ... The electromagnetic spectrum is the range of all types of electromagnetic ... C x-rays. D light.

Fittoniya [83]3 years ago

3 0

Answer:

b i think

Explanation:

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Points

ExtremeBDS [4]

The answer is D. A compound

6 0

3 years ago

How many grams of H 2O are produced from 28.8 g of O 2? (Molar Mass of H 2O = 18.02 g) (Molar Mass of O 2=32.00 g) 4 NH 3 (g) +

krek1111 [17]

Answer: 13.9 g of $H_2O$ will be produced from the given mass of oxygen

Explanation:

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of} O_2=\frac{28.8g}{32.00g/mol}=0.900moles$

The balanced chemical reaction is:

$4NIO_2(g)+7O_2(g)\rightarrow 4NO_2(g)+6H_2O(g)$

According to stoichiometry :

7 moles of $O_2$ produce = 6 moles of $H_2O$

Thus 0.900 moles of $O_2$ will produce = $\frac{6}{7}\times 0.900=0.771moles$ of $H_2O$

Mass of $H_2O=moles\times {\text {Molar mass}}=0.771moles\times 18.02g/mol=13.9g$

Thus 13.9 g of $H_2O$ will be produced from the given mass of oxygen

5 0

3 years ago

Two adaptations to plants are described below:

Elza [17]

Answer:

Explanation: this was easy for me

7 0

3 years ago

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Which material is most likely to be a base?

Goshia [24]

Answer:

Cooffee

Explanation:

<em>the answer is coffee because coffee might be bitter</em>

3 0

4 years ago

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he mineral rhodochrosite [manganese(II) carbonate, MnCO3] is a commercially important source of manganese. Write a half-reaction

valina [46]

Answer:

$MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Explanation:

Half reaction: $MnCO_{3}\rightarrow MnO_{2}$

(1) $CO_{3}$ balance: $MnCO_{3}\rightarrow MnO_{2}+HCO_{3}^{-}$

(2)H and O balance in acidic medium: $MnCO_{3}+2H_{2}O\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

(3) charge balance: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

Hence balanced half-reaction: $MnCO_{3}+2H_{2}O-2e^{-}\rightarrow MnO_{2}+HCO_{3}^{-}+3H^{+}$

7 0

3 years ago

Read 2 more answers