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Serga [27]
3 years ago
6

What positions in society do you think are most valuable?

Advanced Placement (AP)
1 answer:
stiv31 [10]3 years ago
7 0
Some positions in society that are most valuable are being a good and responsible citizen
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A 1.0 kg lump of clay is sliding to the right on a frictionless surface with speed 2 m/s . It collides head-on and sticks to a 0
Aleks [24]

Answer:

0J

Explanation:

Mass of the lump M1 = 1.0 kg, initial velocity of the lump U1 = 2m/s to the right,

mass of the metal sphere M2 = 0.5kg, initial velocity of the metal sphere M2 = -4m/s to the left. using conservation law of momentum;

M1U1 + M2U2 = V (M1 + M2)

(1.0 × 2) + (0.5 × -4) = V (1 + 0.5)

2 -2 = V (1.5)

0 = V (1.5)

divide both side by 1.5

0/1.5 = V 1.5/1.5

V = 0

since final velocity after sticking together of the two masses equals zero then their combined kinetic energy will also equal to zero

1/2 V(M1 +M2)

1/2 ×0 × 1.5 = 0J

3 0
3 years ago
Which of the following expenses would be the most likely to purchased with cash
zavuch27 [327]
Your answer is letter D- Groceries
4 0
3 years ago
Read 2 more answers
17. A toxin increases from 12 ppm to 48 ppm. What percent increase is this?
OLga [1]

Answer:

In order to express the results as a percent, divide the nutrient content (which is expressed in ppm) by 10,000. For example, if the reported value for P2O5 is 2,690 ppm, the calculation to convert to percent would be: 2,690 ppm ÷ 10,000 = 0.269%.

5 0
3 years ago
The regions bounded by the graphs of y=x2 and y=sin2x are shaded in the figure above. What is the sum of the areas of the shaded
Alex Ar [27]

Answer:

The sum of the area of the shaded regions = 0.248685

Explanation:

The sum of the area of the shaded region is given as follows;

The point of intersection of the graphs are;

y = x/2

y = sin²x

∴ At the intersection, x/2 = sin²x

sinx = √(x/2)

Using Microsoft Excel, or Wolfram Alpha, we have that the possible solutions to the above equation are;

x = 0, x ≈ 0.55 or x ≈ 1.85

The area under the line y = x/2, between the points x = 0 and x ≈ 0.55, A₁, is given as follows

1/2 × (0.55)×0.55/2 ≈ 0.075625

The area under the line y = sin²x, between the points x = 0 and x ≈ 0.55, A₂, is given using as follows;

\int\limits {sin^n(x)} \, dx = -\dfrac{1}{n} sin^{n-1}(x) \cdot cos(x) + \dfrac{n-1}{n} \int\limits {sin^{n-2}(x)} \, dx

Therefore;

A_2 = \int\limits^{0.55}_0 {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_0 ^{0.55}

∴ A₂ =1/2 × ((0.55 - sin(0.55)×cos(0.55)) - (0 - sin(0)×cos(0)) ≈ 0.0522

The shaded area, A_{1 shaded} = A₁ - A₂ = 0.075625 - 0.0522 ≈ 0.023425

Similarly, we have, between points 0.55 and 1.85

A₃ = 1/2 × (1.85 - 0.55) × 1/2 × (1.85 - 0.55) + (1.85 - 0.55) × 0.55/2 = 0.78

For y = sin²x, we have;

A_4 = \int\limits^{1.85}_{0.55} {sin^2x} \, dx = \dfrac{1}{2} \left [x -sin(x) \cdot cos(x) \right]_{0.55} ^{1.85} \approx 1.00526

The shaded area, A_{2 shaded} = A₄ - A₃ = 1.00526 - 0.78 ≈ 0.22526

The sum of the area of the shaded regions, ∑A = A_{1 shaded} + A_{2 shaded}

∴ A = 0.023425 + 0.22526 = 0.248685

The sum of the area of the shaded regions, ∑A = 0.248685

8 0
3 years ago
What is the intended purpose of 230 regulations?
cupoosta [38]

Answer:

they would create energry HLADF

Explanation:

7 0
3 years ago
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