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3 years ago

With that informations, we need to find statement of finanical position.

Mathematics

1 answer:

trasher [3.6K]3 years ago

3 0

Answer:

THE ANSWER WOULD BE 4000$

Step-by-step explanation:

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Meg is 6 years older than Victor. Meg's age is 2 years less than five times Victor's age. The equations below model the relation

Verdich [7]

Since no possible correct method is posted, I will suggest a couple.

Method 1: guess and check

Works well for simple problems involving integers like this one.

Victor's age must be zero or greater than one, say one.

Guess v=1, find m=v+6=7, check m=5v-2=5-2=3 no good.

we need to make v bigger

Guess v=2, find m=v+6=2+6=8, check m=5v-2=5*2-2=8 ✔

So v=2, m=8.

Method 2:

Solve the system of two equations.

since the left-hand sides is m in both equations, and since m=m, we just have to equate the right-hand sides to solve for v.

5v-2=v+6

Solve for v

5v-v = 6+2

4v=8

v=2,

so again, v=2, m=v+6=2+6=8.

6 0

3 years ago

Suppose that the bacteria in a colony grow unchecked according to the Law of Exponential Change. The colony starts with 1 bacter

inn [45]

Answer: There are 2.25×10³⁴ bacteria at the end of 24 hours.

Step-by-step explanation:

Since we have given that

Number of bacteria initially = 1

It triples in number every 20 minutes.

So, $\dfrac{20}{60}=\dfrac{1}{3}$

So, our equation becomes

$y=y_0e^{\frac{1}{3}k}\\\\3=1e^{\frac{1}{3}k}\\\\\ln 3=\dfrac{1}{3}k\\\\k=\dfrac{1.099}{0.333}=3.3$

We need to find the number of bacteria that it will contain at the end of 24 hours.

So, it becomes,

$y=1e^{24\times 3.3}\\\\y=e^{79.1}\\\\y=2.25\times 10^{34}$

Hence, there are 2.25×10³⁴ bacteria at the end of 24 hours.

3 0

3 years ago

All of the following relations are functions, except A) y = x2. B) x = y2. C) y = |x|. D) y = x .

elena-s [515]

B) x = y^2 because it fails the vertical line test making it not a function

7 0

3 years ago

Read 2 more answers

How do you solve this

Dmitriy789 [7]

By definition of the trig functions,

$\sin30^\circ=\dfrac y{16}$

$\cos30^\circ=\dfrac x{16}$

We have $\sin30^\circ=\dfrac12$ , so $y=8$ , and $\cos30^\circ=\dfrac{\sqrt3}2$ , so $x=8\sqrt3$ .

Just to check: we should have

$x^2+y^2=16^2$

by the Pythagorean theorem. Indeed,

$8^2+(8\sqrt3)^2=4\cdot8^2=2^2(2^3)^2=2^8=(2^4)^2=16^2$

6 0

3 years ago

When solving graphically ,which system of equations will have exactly one point of intersection

Leno4ka [110]

Slop interest form is the amswer

7 0

3 years ago