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3 years ago

Which quadrant will the figure be located in after a 180 degree rotation?

Mathematics

1 answer:

tiny-mole [99]3 years ago

7 0

Quadrant 2
Cuz it’s gonna be on the opposite side of the graph because it’s 180 degrees

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What is the measure of angle def the tangent chord angle

podryga [215]

OK, If I understand your question correctly your vertex is at E and the arc is defined by ED or DE.
<span>In this case the measure of angle DEF is just 1/2 of the arc length in degrees or 88 degrees.</span>

5 0

4 years ago

Carnival T charges an entrance fee of $7.00 and $0.50 per ticket for the rides. Carnival Q charges an entree fee of $12.00 and $

FrozenT [24]

Answer:

$30

Step-by-step explanation:

Calculation for the tickets that must be purchased for Carnival T and Carnival Q to be the same

Based on the information given let x be the number of ticket to be purchased .

Carnival T entrance fee= $7.00

Ride= $0.50 per ticket

Carnival Q entree fee =12.00

Ride= $0.25 per ticket

Tickets=$7.00 + ($0.50* x) = $12.00 + ($0.25* x)

.25 x = 5.00

Hence:

x=$.25+$5.00

×=$30

Therefore the amount of tickets that must be purchased in order for the total cost at Carnival T and Carnival Q to be the same will be $30

3 0

3 years ago

It was found that the mean length of 100 diodes (LED) produced by a company

Lelechka [254]

Using the normal distribution, it is found that there is a 0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.

<h3>Normal Probability Distribution</h3>

In a normal distribution with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

It measures how many standard deviations the measure is from the mean.

After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.

In this problem, we have that:

The mean is of $\mu = 20.05$ .

The standard deviation is of $\sigma = 0.02$ .

The probability that a diode selected at random would have a length less than 20.01mm is the <u>p-value of Z when X = 20.01</u>, hence:

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{20.01 - 20.05}{0.02}$

$Z = -2$

$Z = -2$ has a p-value of 0.0228.

0.0228 = 2.28% probability that a diode selected at random would have a length less than 20.01mm.

More can be learned about the normal distribution at brainly.com/question/24663213

3 0

2 years ago

1) Determine the discriminant of the 2nd degree equation below:

Aleksandr-060686 [28]

$\LARGE{ \boxed{ \mathbb{ \color{purple}{SOLUTION:}}}}$

We have, Discriminant formula for finding roots:

$\large{ \boxed{ \rm{x = \frac{ - b \pm \: \sqrt{ {b}^{2} - 4ac} }{2a} }}}$

Here,

x is the root of the equation.
a is the coefficient of x^2
b is the coefficient of x
c is the constant term

1) Given,

3x^2 - 2x - 1

Finding the discriminant,

➝ D = b^2 - 4ac

➝ D = (-2)^2 - 4 × 3 × (-1)

➝ D = 4 - (-12)

➝ D = 4 + 12

➝ D = 16

2) Solving by using Bhaskar formula,

❒ p(x) = x^2 + 5x + 6 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5\pm \sqrt{( - 5) {}^{2} - 4 \times 1 \times 6 }} {2 \times 1}}}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm \sqrt{25 - 24} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 5 \pm 1}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 2 \: or - 3}}}$

❒ p(x) = x^2 + 2x + 1 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{ {2}^{2} - 4 \times 1 \times 1} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm \sqrt{4 - 4} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - 2 \pm 0}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = - 1 \: or \: - 1}}}$

❒ p(x) = x^2 - x - 20 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 1) \pm \sqrt{( - 1) {}^{2} - 4 \times 1 \times ( - 20) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{ 1 \pm \sqrt{1 + 80} }{2} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{1 \pm 9}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 5 \: or \: - 4}}}$

❒ p(x) = x^2 - 3x - 4 = 0

$\large{ \rm{ \longrightarrow \: x = \dfrac{ - ( - 3) \pm \sqrt{( - 3) {}^{2} - 4 \times 1 \times ( - 4) } }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm \sqrt{9 + 16} }{2 \times 1} }}$

$\large{ \rm{ \longrightarrow \: x = \dfrac{3 \pm 5}{2} }}$

So here,

$\large{\boxed{ \rm{ \longrightarrow \: x = 4 \: or \: - 1}}}$

<u>━━━━━━━━━━━━━━━━━━━━</u>

5 0

3 years ago

Read 2 more answers

If the equation of a function is y = x2 – 5, what is the output when the input is -1?

Romashka [77]

Answer:

The output is -4

Step-by-step explanation:

y = x^2 – 5

Let x=-1

y = (-1)^2 -5

= 1-5

=-4

8 0

3 years ago