Here is the formula that your going to need to use A=P(1+r/n)^nt
So P=500, R=0.082, N=1, T=15
Plug it into your equation and you have A=500(1+0.082/1)^(1)(15)
Simplify what's in the parenthesis A=500(1.082)^(1)(15)
Multiply your exponents A=500(1.082)^15 Then A=500(3.26)
Finally you multiply your last two numbers to get A=1,630
So after 15 years you would have $1,630
I hope this helped you :)
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60
The equation used would be:
4m + 2 = 30
where the answer would be 7.
Answer:
b = y-intercept
Step-by-step explanation:
Answer:
35
Step-by-step explanation:
All you need to do is substitute!
(3x2)^2-1
6^2-1
36-1
= 35
Hope this helps!!