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madreJ [45]
3 years ago
6

A slice is made parallel to the base of a right rectangular pyramid, as shown. What is the area of the resulting two-dimensional

cross-section? Enter your answer in the box.
Rectangular pyramid intersected horizontally by a rectangle. The front edge of the base of the pyramid is labeled 7 millimeters, and the right edge is labeled 4 millimeters. The height of the pyramid is labeled 5 millimeters. The part of the larger rectangle that intersects the pyramid is a smaller gray rectangle. The front side of the smaller rectangle is labeled 3.5 millimeters, and the right side is labeled 2 millimeters.
Mathematics
1 answer:
hodyreva [135]3 years ago
8 0

Answer:

  7 mm²

Step-by-step explanation:

The area of any rectangle is the product of its side lengths. The area of the cross section is the product of its dimensions:

  (3.5 mm)·(2 mm) = 7 mm²

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Answer:

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Step-by-step explanation:

The given values are:

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As we know,

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⇒  SI=\frac{P\times R\times T}{100}

On putting the values, we get

⇒       =\frac{3700\times 8.5\times \frac{1}{2} }{100}

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⇒  P+SI

⇒  3700+157.25

⇒  3,857.25 ($)

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