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Veronika [31]
3 years ago
12

I need help I don’t know this help

Mathematics
2 answers:
Paraphin [41]3 years ago
8 0
They're both functions because each input has exactly one output
Tom [10]3 years ago
3 0
They are both functions so put test
You might be interested in
PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
1 year ago
Can someone please help me find x.
Sergeeva-Olga [200]

Answer:

  • We have similar triangles
  • Hence 6x+2=x+3
  • 5x=1
  • x=1/5

6 0
3 years ago
Find the area of the circle below.<br> 12 cm
QveST [7]

Answer:

About 113.1

Step-by-step explanation:

Area of a circle= πr2

Radius= 6

6x6=36

36π= About 113.1

3 0
4 years ago
Read 2 more answers
Find the volume of the cylinder.
Sav [38]

Answer:

In a sequence described by a function, what does the notation f(3) = 1 mean?

ОА. .

The common difference of the sequence is 3.

OB.

The first term in the sequence has a value of 3.

O c.

The common ratio of the sequence is 3.

OD.

The third term in the sequence has a value of 1.

7 0
3 years ago
U can start immediately I already got the answer I just need to see if i got it right and understand
umka21 [38]

ANSWER

80 units²

EXPLANATION

One way to solve this is to find the area of the blue square and the subtract the areas of the red triangles:

The blue square is 12 units long by 12 units wide. Its area is:

A_{\text{square}}=12\times12=144

Then, the area of the big triangle, which has a base 12 units long and a height of 10 units, is:

A_{\text{traingle}1}=\frac{12\times10}{2}=\frac{120}{2}=60

The smaller triangle has a base of 4 units and a heigth of 2 units. Its area is:

A_{\text{triangle}2}=\frac{4\times2}{2}=\frac{8}{2}=4

So the total area of the figure is:

\begin{gathered} A=A_{\text{square}}-A_{triangle1}-A_{triangle2} \\ A=144-60-4 \\ A=80 \end{gathered}

8 0
2 years ago
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