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alekssr [168]
3 years ago
10

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Answer:

9.5

Step-by-step explanation:

Find the sample variance for the data 9,12,9,14,6. Round the answer to one decimal place. Sample variance.

Step 1

We find the Mean of the numbers

Mean = Sum of terms/ Number of terms

Mean = 9+12+9+14+6/5

= 50/5

= 10

Step 2

We find the sample variance

Formula =

(x - Mean)²/n - 1

n = 5

= (9 - 10)²+(12 -10)²+(9- 10)²+(14-10)²+(6-10)²/5 - 1

= 1+ 4+ 1+ 16+16/5 - 1

= 38/5 - 1

= 38/4

= 9.5

Therefore, Sample variance = 9.5

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This shape is separated into two trapezoids. The equation for the area of a trapezoid is .5(base1 + base2) multiplied by height. Therefore, each half of the compound shape would be equal to .5(12 + 8) * 6 or 10 * 6 = 60. So the area of the total would be 60+60 or 120.
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3 years ago
1+2+3+4+5+6+7+8+9+1+2+3+4+5+6+7+8+9+10 times 2
Maksim231197 [3]

Answer:

200

Step-by-step explanation:

<u>Step 1:  Add</u>

1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10

1 + 2 = 3

3 + 3 = 6

6 + 4 = 10

10 + 5 = 15

15 + 6 = 21

21 + 7 = 28

28 + 8 = 36

36 + 9 = 45

45 + 1 = 46

46 + 2 = 48

48 + 3 = 51

51 + 4 = 55

55 + 5 = 60

60 + 6 = 66

66 + 7 = 73

73 + 8 = 81

81 + 9 = 90

90 + 10 = 100

<em>100</em>

<u>Step 2:  Multiply</u>

100 * 2

<em>200</em>

Answer:  200

6 0
2 years ago
The circumference of a circle is 47.1 feet. What is the diameter of the circle? 7.5 ft 15 ft 147.9 ft 30 ft
MAVERICK [17]
Hi Zack! Thanks for asking a question here on Brainly.

█ Explanation <span>█
</span>
<span>✦ We are looking to find the diameter of the circle.
</span>✦ Do the following formula to find the diameter.
✦ 47,1/ \pi =47.1/3.14
<span>✦ = 15 ft 
</span>
Answer: 15 ft 

<span>Hope that helps! ★ <span>If you have further questions about this question or need more help, feel free to comment below or leave me a PM. -UnicornFudge aka Nadia </span></span>
6 0
3 years ago
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Jlenok [28]
I think that its 36...

6 0
3 years ago
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A simple random sample of 100 observations was taken from a large population. The sample mean and the standard deviation were de
olga2289 [7]

Answer:

Se=1.2

Step-by-step explanation:

The standard error is the standard deviation of a sample population. "It measures the accuracy with which a sample represents a population".

The central limit theorem (CLT) states "that the distribution of sample means approximates a normal distribution, as the sample size becomes larger, assuming that all samples are identical in size, and regardless of the population distribution shape"

The sample mean is defined as:

\bar X =\frac{\sum_{i=1}^n x_i}{n}

And the distribution for the sample mean is given by:

\bar X \sim N(\mu,\frac{\sigma}{\sqrt{n}})

Let X denotes the random variable that measures the particular characteristic of interest. Let, X1, X2, …, Xn be the values of the random variable for the n units of the sample.

As the sample size is large,(>30) it can be assumed that the distribution is normal. The standard error of the sample mean X bar is given by:

Se=\frac{\sigma}{\sqrt{n}}

If we replace the values given we have:

Se=\frac{12}{\sqrt{100}}=1.2

So then the distribution for the sample mean \bar X is:

\bar X \sim N(\mu=80,Se=1.2)

5 0
3 years ago
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