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Anarel [89]
3 years ago
10

Multiply (6v+5)(412-2v+7) then simplify the expression

Mathematics
2 answers:
Lunna [17]3 years ago
5 0
Simplified answer,, -12v^2+2504v+2095
faust18 [17]3 years ago
4 0

Answer: =-12v^2+2504v+2095

Step-by-step explanation:

Given the expression:

(6v+5)(412-2v+7)

You need to apply Distributive property, but first remember the multiplication of signs:

(+)(+)=+\\(+)(-)=-\\(-)(-)=+

Then:

(6v+5)(412-2v+7)=2472v-12v^2+42v+2060-10v+35

Finally, you can simplify the expression by adding the like terms:

=-12v^2+2504v+2095

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Which is Bigger?
igomit [66]
A)
43\%=\frac{43}{100} \\ \\
\frac{24}{60}=\frac{4}{10}=\frac{40}{100} \\ \\
43>40 \Rightarrow \frac{43}{100} > \frac{40}{100} \Rightarrow 43\% > \frac{24}{60}

43% is bigger.

b)
\frac{18}{30}=\frac{6}{10}=\frac{60}{100} \\ \\
0.51=\frac{51}{100} \\ \\
60>51 \Rightarrow \frac{60}{100} > \frac{51}{100} \Rightarrow \frac{18}{30} >0.51

18/30 is bigger.
3 0
3 years ago
Х = 3y — 1<br> 3х – бу = 12
Georgia [21]
Answer: x=14 and y=5

Work:
7 0
3 years ago
Read 2 more answers
400 is decreased 60 amount of change
alukav5142 [94]
400 to 400-60 which is 340

Does this helps you?
I hope it does but tell me if it doesn't.

3 0
3 years ago
Read 2 more answers
Pleaaase help this is due today
Murrr4er [49]

Answer:

a = false

b= true

c= false

d= false

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8 0
2 years ago
Read 2 more answers
The 12th term of a sequence is 41 and the 15th term is 140. What is the nth term?
OLga [1]
An= mth term.
an=a₁+(n-1)*d

a₁₂=41
a₁₅=140

a₁₂=41
41=a₁+(12-1)*d
41=a₁+11d 
a₁+11d=41    (1)

a₁₅=140
140=a₁+(15-1)*d
140=a₁+14d 
a₁+14d=140    (2)

With the equiations (1) and (2)  build a system of equations
a₁+11d=41
a₁+14d=140

we solve it.
-(a₁+11d=41)
  a₁+14d=140
--------------------
       3d=99  ⇒d=99/3=33

a₁+11d=41
a₁+(11*33)=41
a₁+363=41
a₁=41-363=-322

an=a₁+(n-1)*d
an=-322+(n-1)*33
an=-322+33n-33
an=-355+33n

an=-355+33n

To check:
a₁₂=-355+33*12=-355+396=41
a₁₅=-355+33*15=-355+495=140.
3 0
3 years ago
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