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Anarel [89]
3 years ago
10

Multiply (6v+5)(412-2v+7) then simplify the expression

Mathematics
2 answers:
Lunna [17]3 years ago
5 0
Simplified answer,, -12v^2+2504v+2095
faust18 [17]3 years ago
4 0

Answer: =-12v^2+2504v+2095

Step-by-step explanation:

Given the expression:

(6v+5)(412-2v+7)

You need to apply Distributive property, but first remember the multiplication of signs:

(+)(+)=+\\(+)(-)=-\\(-)(-)=+

Then:

(6v+5)(412-2v+7)=2472v-12v^2+42v+2060-10v+35

Finally, you can simplify the expression by adding the like terms:

=-12v^2+2504v+2095

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(b) For those values of k, verify that every member of the family of functions y = A sin(kt) + B cos(kt) is also a solution. y =
frutty [35]

Answer:

Check attachment for complete question

Step-by-step explanation:

Given that,

y=Coskt

We are looking for value of k, that satisfies 4y''=-25y

Let find y' and y''

y=Coskt

y'=-kSinkt

y''=-k²Coskt

Then, applying this 4y'"=-25y

4(-k²Coskt)=-25Coskt

-4k²Coskt=-25Coskt

Divide through by Coskt and we assume Coskt is not equal to zero

-4k²=-25

k²=-25/-4

k²=25/4

Then, k=√(25/4)

k= ± 5/2

b. Let assume we want to use this

y=ASinkt+BCoskt

Since k= ± 5/2

y=A•Sin(±5/2t)+ B •Cos(±5/2t)

y'=±5/2ACos(±5/2t)-±5/2BSin(±5/2t)

y''=-25/4ASin(±5/2t)-25/4BCos(±5/2t

Then, inserting this to our equation given to check if it a solution to y=ASinkt+BCoskt

4y''=-25y

For 4y''

4(-25/4ASin(±5/2t)-25/4BCos(±5/2t))

-25A•Sin(±5/2t)-25B•Cos(±5/2t).

Then,

-25y

-25(A•Sin(±5/2t)+ B •Cos(±5/2t))

-25A•Sin(±5/2t) - 25B •Cos(±5/2t)

Then, we notice that, 4y'' is equal to -25y, then we can say that y=Coskt is a solution to y=ASinkt+BCoskt

4 0
3 years ago
Which ones are the distance formula and midpoint formula?
lutik1710 [3]

Answer:

The distance formula is d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)2}

The midpoint formula is \left(\frac{x_1\:+x_2}{2}\right),\left(\frac{y_1-y_2}{2}\right)

Step-by-step explanation:

apply the pythagorean theorem on a coordinate grid

7 0
3 years ago
I. am. tired. of. posting. questions. over. and. over. again. I so serious this is a grade and today is my last day of school an
aleksklad [387]

Answer:hi

Step-by-step explanation:plz like and brainliest i am noob I really need this plz

3 0
2 years ago
Read 2 more answers
I need help please ​
bija089 [108]

Hey There!

Lets Just Work through your answers,

ⓧ A - An isosceles triangle is a triangle with (at least) two equal sides, so this would not apply to the given triangle.

:) B - A scalene triangle is a triangle in which all three sides have different lengths so this applies to the given triangle. One side measures 10, one measures 11, and one measures 12.1

ⓧ C - A right triangle is a type of triangle that has one angle that measures 90 degrees, which this triangle does not so this does not apply.

ⓧ D - In geometry, an equilateral triangle is a triangle in which all three sides are equal, so this does not apply to the given triangle.

ⓧ E - An obtuse triangle is a triangle with one obtuse angle (greater than 90°) and two acute angles, so this does not apply to the given triangle.

:) F - An acute triangle (or acute-angled triangle) is a triangle with three acute angles less than 90 degrees. So this applies to the given triangle.

In Summary, B & F classify the given triangle correctly.

If you could rate five starts & give brainliest that would be greatly appreciated!

Hope I helped, Have a good day.

4 0
3 years ago
betty closes the nozzle and fills it completely with a liquid. She then opens the nozzle. If the liquid drips at the rate of 14
natta225 [31]

Answer:

4.71 minutes

Step-by-step explanation:

Incomplete question [See comment for complete question]

Given

Shape: Cone

r = 3 -- radius

h = 7 --- height

Rate = 14in^3/min

Required

Time to pass out all liquid

First, calculate the volume of the cone.

This is calculated as:

V = \frac{1}{3} \pi r^2h

This gives:

V = \frac{1}{3} * 3.14 * 3^2 * 7

V = \frac{1}{3} * 197.82

V = 65.94in^3

To calculate the time, we make use of the following rate formula.

Rate = \frac{Volume}{Time}

Make Time the subject

Time= \frac{Volume}{Rate }

This gives:

Time= \frac{65.94in^3}{14in^3/min}

Time= \frac{65.94in^3}{14in^3}min

Cancel out the units

Time= \frac{65.94}{14} min

Time= 4.71 min\\

3 0
2 years ago
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