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pishuonlain [190]
3 years ago
9

Multiple choice helpppppppppppppppppppppppp

Mathematics
1 answer:
Tresset [83]3 years ago
6 0

Answer:

2nd number is correct

Here's your solution

=> 2p(-3p^2 + 4p - 5)

=> multiple 2p with whole

=>. -6p^3 + 8p^2 - 10p

this is your answer

hope it helps

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Solve the equation. 20x-7=5+16x
Evgesh-ka [11]
20x-7= 5+16x

Add 7 to both sides
20x= 12+16x

Subtract 16x from both sides
4x=12

Divide both sides by 4
x=3

Final answer: x=3
6 0
3 years ago
Read 2 more answers
Helpppppppppppp plzzzzzzzzzzzzzzzzzzz
ZanzabumX [31]

Answer:

Step-by-step explanation:

\left[\begin{array}{ccc}7&31\\142&19\end{array}\right] = 7(19) - 142(31) = <em>- 4269</em>

\left[\begin{array}{ccc}7&11&21\\55&-8&2\\-16&-1&-9\end{array}\right] = 7(- 8)(- 9) + 11(2)(- 16) + 21(55)(- 1) - 21(- 8)(- 16) - 7(2)(- 1) - 11(55)(- 9) = <em>1768</em>

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4 0
3 years ago
The perimeter of a triangle is 50 ft. What is the value of x?
ioda
The answer is 20.5

Subtract both 7.5 and 22 from 50

50-7.5 = 42.5

42.5 - 22 = 20.5

Hope this helps :)
8 0
3 years ago
What is the value of N?
son4ous [18]

Answer:

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Step-by-step explanation:

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3 0
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Starting at time t = 0, the altitude of one helicopter is given by A1 = 600 + 150t, and the altitude of a second helicopter is g
natta225 [31]

Answer:

The equation for difference in altitude of the two helicopters is A =  650 - 100t

Step-by-step explanation:

Given;

The altitude of one helicopter is, A1 = 600 + 150t

The altitude of a second helicopter is,  A2 = 1250 + 50t

Their difference in altitude, A at time t, is calculated as

A₂ - A₁  = A = (1250 + 50t) - (600 + 150t)

A₂ - A₁  = A =  1250 + 50t - 600 -150t

A₂ - A₁  = A = 1250 - 600 + 50t - 150t

A₂ - A₁  = A =  650 - 100t

Therefore, the equation for difference in altitude of the two helicopters is A =  650 - 100t

3 0
4 years ago
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