Which of the following statements about cylinder placement are true?

Clothing made of several thin layers of fabric with trapped air in between, often called ski clothing, is commonly used in cold

Pavlova-9 [17]

Answer:

Q=127.66W

L=9.2mm

Explanation:

Heat transfer consists of the propagation of energy in the form of heat in different ways, these can be convection if it is through a fluid, radiation through electromagnetic waves and conduction through solid solids.

To solve any problem related to heat transfer, the general equation is used

Q = delta / R

Where

Q = heat

Delta = the temperature difference

R = is the thermal resistance by conduction, convection and radiation

to solve this problem we propose the previous equation

Q = delta / R

later we find R

$R=[tex]r=\frac{6L1}{AK1} +\frac{5L2}{AK2}+\frac{1}{Ah}$

$R=\frac{6(0.0001)}{(1.25)(0.026)} +\frac{5(0.012)}{(1.25)(0.026)}+\frac{1}{(25)(1.25)} =0.235 K/w$

Q=(25-(-5))/0.235=127.66W

part b

we use the same ecuation with Q=127.66

Q = delta / R

Δ $R=\frac{L}{KA} +\frac{1}{hA} \\R=\frac{L}{(0.035)(1.25)} +\frac{1}{(25)(1.25)}\\ R=22.85L+0.032\\Q=(T1-T2)/R\\\\127.66=(25-(-5))/(22.85L+0.032)\\solving for L\\L=9.2mm$

6 0

3 years ago

A 9-m length of 6-mm-diameter steel wire is to be used in a hanger. The wire stretches 18mm when a tensile force P is applied. I

worty [1.4K]

Force P is 11304 N and normal stress is 400 N/mm²

Explanation:

Given-

Length, l = 9 m = 9000 mm

Diameter, d = 6 mm

Radius, r = 3 mm

Stretched length, Δl= 18 mm

Modulus of elasticity, E = 200 GPa = 200 X 10³MPa

Force, P = ?

According to Hooke's law,

Stress is directly proportional to strain.

So,

σ ∝ ε

σ = E ε

Where, E is the modulus of elasticity

We know,

ε = Δl / l

So,

σ = E X Δl/l

σ =

$200 X 10^3 * \frac{18}{9000} \\\\ = 400N/mm^2$

We know,

σ = P/A

And A = π (r)²

σ = P / π (r)²

$400 N/mm^2 = \frac{P}{3.14 X (3)^2} \\\\400 = \frac{P}{28.26} \\\\P = 11304N$

Therefore, Force P is 11304 N and normal stress is 400 N/mm²

4 0

4 years ago

Is a water proof material used around tubs and

Leviafan [203]

I think it’s hard board

4 0

3 years ago

Read 2 more answers

1. A wood board is one of a dozen different parts in a homemade robot kit. The width, depth, and height dimensions of the board

otez555 [7]

Answer:

183.75 cubic inches.

Explanation:

The volume of the wood board is determine by means of this expression:

$V = w \cdot h \cdot l$

By replacing variables:

$V = (7.5 in) \cdot (14 in) \cdot (1.75 in)\\V = 183.75 in^{3}$

3 0

3 years ago

1. Two aluminium strips and a steel strip are to be bonded together to form a composite bar. The modulus of elasticity of steel

yarga [219]

Answer:

1.933 KN-M

Explanation:

Determine the largest permissible bending moment when the composite bar is bent horizontally

Given data :

modulus of elasticity of steel = 200 GPa

modulus of elasticity of aluminum = 75 GPa

Allowable stress for steel = 220 MPa

Allowable stress for Aluminum = 100 MPa

a = 10 mm

First step

determine moment of resistance when steel reaches its max permissible stress

next : determine moment of resistance when Aluminum reaches its max permissible stress

Finally Largest permissible bending moment of the composite Bar = 1.933 KN-M

attached below is a detailed solution

5 0

3 years ago