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ZanzabumX [31]
3 years ago
8

The efficiency of an electric motor is 80%. If it supplies 6 kW of rotational output power, calculate the amount of electrical i

nput power consumed. (A)7.0kW (B)7.5 kW (C)8.0 kW (D)8.5 kW
Engineering
1 answer:
amid [387]3 years ago
4 0

Answer:

(B)

\eta=7.5kW

Explanation:

It is actually an easy problem, the energy efficiency is a dimensionless number, which is the report that indicates what can be recovered profitably from the machine from what has been spent to make it work. It is defined as:

\eta=\frac{P_o_u_t}{P_i_n}

Where:

P_o_u_t= Output power.

P_i_n= Input power.

Replacing the data given by the problem:

0.8=\frac{6000}{P_i_n}

Isolating P_i_n

P_i_n=\frac{6000}{0.8} =7500W=7.5kW

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