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ELEN [110]
3 years ago
14

HELP PLEASEEE!!! ILL GIVE BRAINLIEST

Mathematics
1 answer:
lana [24]3 years ago
8 0

Answer:

A:8yd

B:2ft

Step-by-step explanation:

A.....All sides of a square are equal and a square has four side so take 32yd/4 and get 8

B.....square root of 4

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A set of input and output values, such that each input has one or more outputs, is called a
Ainat [17]

Answer:

function  

Step-by-step explanation: A function is the one where you put an input to find x or y


5 0
3 years ago
Helpppppp meeeeee plzzz
mafiozo [28]

group1 a = 0.25

group1 b = 0.75


group2 a = 0.44

group2 b = 0.56

6 0
3 years ago
What is the equation of this line?
Mamont248 [21]
(0, -3)(2, -2)
slope = (-2 + 3)/(2-0) = 1/2

b = -3
equation
y = 1/2x - 3

answer is A
<span>y = 1/2x - 3</span>
3 0
4 years ago
Read 2 more answers
Complementary events must have a sum of 1.
Bas_tet [7]

This is a true statement.

Consider two events A and B. We say they are complementary if P(A)+P(B) = 1

This means that either event A or event B must happen, since the "1" represents 100% probability. Having a probability of 100% means absolute certainty.

---------

Example:

A = the event it rains

B = the event it does not rain

P(A) = 0.30 = 30% chance of rain

P(B) = 0.70 = 70% chance it does not rain

P(A)+P(B) = 0.30+0.70 = 1

So this shows the two events are complementary.

8 0
4 years ago
A) How many ways can 2 integers from 1,2,...,100 be selected
Anna007 [38]

Answer with explanation:

→Number of Integers from 1 to 100

                                            =100(50 Odd +50 Even)

→50 Even =2,4,6,8,10,12,14,16,...............................100

→50 Odd=1,3,,5,7,9,..................................99.

→Sum of Two even integers is even.

→Sum of two odd Integers is odd.

→Sum of an Odd and even Integer is Odd.

(a)

Number of ways of Selecting 2 integers from 50 Integers ,so that their sum is even,

   =Selecting 2 Even integers from 50 Even Integers , and Selecting 2 Odd integers from 50 Odd integers ,as Order of arrangement is not Important, ,

        =_{2}^{50}\textrm{C}+_{2}^{50}\textrm{C}\\\\=\frac{50!}{(50-2)!(2!)}+\frac{50!}{(50-2)!(2!)}\\\\=\frac{50!}{48!\times 2!}+\frac{50!}{48!\times 2!}\\\\=\frac{50 \times 49}{2}+\frac{50 \times 49}{2}\\\\=1225+1225\\\\=2450

=4900 ways

(b)

Number of ways of Selecting 2 integers from 100 Integers ,so that their sum is Odd,

   =Selecting 1 even integer from 50 Integers, and 1 Odd integer from 50 Odd integers, as Order of arrangement is not Important,

        =_{1}^{50}\textrm{C}\times _{1}^{50}\textrm{C}\\\\=\frac{50!}{(50-1)!(1!)} \times \frac{50!}{(50-1)!(1!)}\\\\=\frac{50!}{49!\times 1!}\times \frac{50!}{49!\times 1!}\\\\=50\times 50\\\\=2500

=2500 ways

7 0
3 years ago
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