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4 years ago

A money box contains only 10-cent

Mathematics

1 answer:

AysviL [449]4 years ago

3 0

Answer:

Number of 10 cents = 18

Number of 20 cents = 10

Step-by-step explanation:

Let number of 10 cents be = x

Let number 20 cents be = y

Total number of coins = x + y = 28 -------- ( 1 )

Total amount in the box = 0.10 x + 0.20y = 3.80 ---------- ( 2 )

Solve the equations to find x and y

( 1 ) => x + y = 28

x = 28 - y

Substitute x in ( 2 )

( 2 ) => 0.10(28 - y) + 0.20y = 3.80

2.80 - 0.10y + 0.20y = 3.80

0.10 y = 3.80 - 2.80

0.10 y = 1.00

$y = \frac{1}{0.10} = 10$

y = 10

Substitute y in ( 1 ) => x + y = 28

x + 10 = 28

x = 28 - 10

x = 18

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Anyone know this question?

Hitman42 [59]

Answer:

16π square centimeters.

Step-by-step explanation:

The area of a circle is πr².

Here, we are given the diameter, but we just need to divide it by 2 to get the radius.

8/2 = 4

So, the radius is 4 cm.

Now, we can substitute it into the formula to find the area.

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3 years ago

Almost done help......

Anton [14]

Answer:

x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A

Step-by-step explanation:

See steps below;

I would prefer answering this question by completing the square, rather than applying a quadratic formula;

3x^2 - 6x - 12 = 0, ⇒ Add 12 to either side,

3x^2 - 6x = 12, ⇒ Divide either side by 3,

x^2 - 2x = 4, ⇒ Write the equation in the form x^2 + 2ax + a^2 = (x + a)^2,

x^2 - 2ax + a^2 = 4 + a^2, ⇒ Solve for a

2ax = -2x,

a = - 1, ⇒ Substitute value of a,

x^2 - 2x + 1 = 4 + 1,

( x - 1 )^2 = 5, ⇒ Solve for x,

x = √5 + 1, and x = - √5 + 1,

In other words; Solution : x = 1 + ( √ 10 )/ 2, or x = 1 - ( √ 10 )/ 2; Option A

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4 years ago

The first term of an arithmetic sequence is five the 11th term is 125 what is the common difference of the arithmetic sequence?

GaryK [48]

Answer:

Step-by-step explanation:

y = 5

y + 10x = 125

5 + 10x= 125

10x = 120

x = 12

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3 years ago

Select the correct answer.

Marta_Voda [28]

Answer: Step 5

===================================================

Reason:

The order of operations is PEMDAS

P = parenthesis
E = exponents
M = multiplication
D = division
A = addition
S = subtraction

The multiplication and division are on the same level of precedent, and the same goes for addition and subtraction. Some math textbooks may refer to PEMDAS as BODMAS, which is basically the same thing.

Notice how division comes before addition. So we must compute the $10 \div 2$ portion first before adding in step 4.

This is what steps 4 and onward should look like

$2 + 10 \div 2\\\\2 + 5\\\\7$

So that's why the error is in step 5

If there was parenthesis around the "2+10", and we had $(2+10) \div 2$ , then step 5 given by your teacher would be correct.

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2 years ago

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Anarel [89]

Answer:

Step-by-step explanation:

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