How to solve your problem
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5)(4x-3)(-2x^{2}-7x-5)(4x−3)(−2x2−7x−5)
Simplify
1
Distribute
(4−3)(−22−7−5)
(4x−3)(−2x2−7x−5){\color{#c92786}{(4x-3)(-2x^{2}-7x-5)}}(4x−3)(−2x2−7x−5)
4(−22−7−5)−3(−22−7−5)
2
distribute
4(−22−7−5)−3(−22−7−5)
4x(−2x2−7x−5)−3(−2x2−7x−5){\color{#c92786}{4x(-2x^{2}-7x-5)}}-3(-2x^{2}-7x-5)4x(−2x2−7x−5)−3(−2x2−7x−5)
−83−282−20−3(−22−7−5)
3
−83−282−20−3(−22−7−5)
−8x3−28x2−20x−3(−2x2−7x−5)-8x^{3}-28x^{2}-20x{\color{#c92786}{-3(-2x^{2}-7x-5)}}−8x3−28x2−20x−3(−2x2−7x−5)
−83−282−20+62+21+15
4
Solution
−83−222++15
I know this looks like a lot but its just how you solve your problem.
therefor, your answer is
Solution
−83−222++15
<em>Hope this helps!</em>
<em>Have a great day!</em>
<em>-Hailey</em>
1 and 2
because you can do the math and it works:
1+2=3
1*2=2
Temperature at noon: Tn=-2.9 f
Rate: r=+1.3 f/h
Total decreased: d=-3.7 f
Temperature at midnight: Tm=?
Tm=Tn+r(6 p.m.-12 m)+d
Tm=-2.9 f+(1.3 f/h)(18 h-12 h)+(-3.7 f)
Tm=-2.9 f+(1.3 f/h)(6 h)-3.7 f
Tm=-2.9 f+7.8 f-3.7 f
Tm=1.2 f
Answer: T<span>he temperature at midnight was 1.2 f</span>
Answer:
12. h=3
13. h=-3
Step-by-step explanation:
12. Recall that 
is a horizontal shift since h is being applied within the operation to the input. This means that h will slide the function left or right. Since the function f has a point at (1,-2) and g has the same point at (4,-2) then the function has moved 3 units 1+3=4 to the right. h=3.
13. Once again, h is a horizontal shift meaning the graphs has moved left or right only. Looking at g it has a point at (-2,2) while f has the same point at (1,2). So the graph f has moved to the left 3 units. This is h=-3 since 1+-3 = -2.
