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3 years ago

4 divided by 992 because my calculator isn't helping and i'm not trynna fail

Mathematics

1 answer:

Black_prince [1.1K]3 years ago

4 0

Answer:

4/992 = 0.00403225806

Step-by-step explanation:

I hope this helps!!

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Please help me with algebra part B and C. attachment below. Will mark as brainslist. 25 points.

miv72 [106K]

Answer:

C. $(-7x+60)(x+4)$

Step-by-step explanation:

Consider the expression $-7x^2+32x+240.$

First, note that

$a=-7\\ \\b=32\\ \\c=240$

Find the discriminant

$D=b^2-4ac=32^2-4\cdot (-7)\cdot 240=1,024+6,720=7,744\\ \\\sqrt{D}=\sqrt{7,744}=88$

Now,

$x_1=\dfrac{-b+\sqrt{D}}{2a}=\dfrac{-32+88}{2\cdot (-7)}=-4\\ \\x_2=\dfrac{-b-\sqrt{D}}{2a}=\dfrac{-32-88}{2\cdot (-7)}=\dfrac{60}{7}$

Write the factored form:

$-7x^2+32x+240=-7(x-(-4))\left(x-\dfrac{60}{7}\right)=(x+4)(-7x+60)$

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3 years ago

Two linear functions, f(x) and g(x), are combined by addition to form h(x). The same two linear functions are combined by multip

weqwewe [10]

Answer: this is the right answer Graph A represents j(x). The y-intercepts for f(x) and g(x) can be 1 and 3. And The rate of change of the sum of f(x) and g(x) is greater than that of either function. your welcome

Step-by-step explanation:

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4 years ago

For an angle 0 with the point (-20,-21) on its terminating side, what is the value of cosine ?

Karo-lina-s [1.5K]

check the picture below.

$\bf (\stackrel{a}{-20},\stackrel{b}{-21})\impliedby \textit{let's find the \underline{hypotenuse}} \\\\\\ \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=\sqrt{a^2+b^2} \qquad \begin{cases} c=hypotenuse\\ a=\stackrel{adjacent}{-20}\\ b=\stackrel{opposite}{-21}\\ \end{cases} \\\\\\ c=\sqrt{(-20)^2+(-21)^2}\implies c=\sqrt{841}\implies c=29 \\\\[-0.35em] ~\dotfill\\\\ ~\hfill cos(\theta )=\cfrac{\stackrel{adjacent}{-20}}{\stackrel{hypotenuse}{29}}~\hfill$

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3 years ago

Write the coordinates of the vertices after a reflection over the y-axis.

vampirchik [111]

Answer:

J'(9'9)

K'(0,9)

L'(0,0)

M'(-9,0)

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2 years ago

Trigonometry pile up. Anyone mind helping me out with this one?

S_A_V [24]

$cos34^o=\frac{8}{a};\ cos34^o\approx0.829\\\\\frac{8}{a}=0.829\to a\approx9.65\\\\9.65-2.5+3.6=10.75\\\\cos11^o=\frac{b}{10.75};\ cos11^o\approx0.981\\\\\frac{b}{10.75}=0.981\to b\approx10.55\\\\10.55-2.1+2.9=11.35\\\\c^2+3.8^2=11.35^2\\\\c^2=11.35^2-3.8^2\\\\c\approx10.69$

$10.69-3.2=7.49\\\\tan42^o=\frac{d}{7.49};\ tan42^o\approx0.9\\\\\frac{d}{7.49}=0.9\to d\approx6.74\\\\sin37^o=\frac{6.74}{e};\ sin37^o\approx0.602\\\\\frac{6.74}{e}=0.602\to e\approx11.2\\\\11.2+4.3=15.5\\\\sin53^o=\frac{f}{15.5};\ sin53^o\approx0.8\\\\\frac{f}{15.5}=0.8\to f\approx12.4$

$12.4-2.2=10.2\\\\g^2=10.2^2+1.7^2\to g\approx10.34\\\\cos21^o=\frac{10.34}{h};\ cos21^o\approx0.934\\\\\frac{10.34}{h}=0.934\to h=11.07\\\\11.07+1.7=12.77\\\\sin71^o=\frac{x}{12.77};\ sin71^o\approx0.946\\\\\frac{x}{12.77}=0.946\to x\approx12.1\ (cm)\leftarrow Answer$

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3 years ago