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kotegsom [21]
1 year ago
15

Write the coordinates of the vertices after a reflection over the y-axis.

Mathematics
1 answer:
vampirchik [111]1 year ago
3 0

Answer:

J'(9'9)

K'(0,9)

L'(0,0)

M'(-9,0)

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Write g-12 in words
larisa [96]
I'm guessing you are looking for an algebraic sentence. In that case, 12 less than g would make sense, or 12 subtracted from g
8 0
3 years ago
Tyler was shoving an equation and his last line of work read -12=12. What does this mean
wolverine [178]

Answer:

Step-by-step explanation:

-12 = 12 ....this is incorrect...meaning no solutions

**

if it ended in :

x = a number, or y = a number...means there is 1 solution

if it ended in :

-12 = 12....incorrect answer, means there is no solutions

if it ended in :

2 = 2 or -4 = -4....correct answer, but not variable...means infinite solutions

6 0
2 years ago
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Need help with 4-10 pleaseeee
emmainna [20.7K]

Answer:

-6

Step-by-step explanation:

10 - 4 = 6

Turn it to negative.

-6

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3 years ago
A line segment on a number line has its endpoints at -9 and 6. what is midpoint
ivolga24 [154]
Midpoint formula = (-9 + 6) / 2 = -3/2
8 0
3 years ago
Please help me i don't know what to do <br> please show your work
Diano4ka-milaya [45]
<h3>Distributive Property</h3>

The distributive property lets you group or ungroup terms using parentheses. It lets you multiply an external factor by every term in parentheses, expressing the result as a sum:

... a(b + c) = ab + ac . . . . . . factor <em>a</em> multiplies the terms <em>b</em> and <em>c</em>

and it lets you remove a common factor from different terms, putting that factor outside parentheses:

... ab + ac = a(b + c)

The letters <em>a</em>, <em>b</em>, <em>c</em> here can stand for any number or expression.

<h3>Homework</h3>

20. To do this problem, you need to eliminate the parentheses using the distributive property. Then, "collect terms," which is another application of the distributive property. The external factor outside the parentheses is (-2/3). Multiply that by each term in parentheses, and add the results.

After that, recognize that c is a factor of two of the terms. Add their coefficients to simplify that sum to one term.

-\dfrac{2}{3}(12c-9)+14c=\left(-\dfrac{2}{3}\right)(12c)+\left(-\dfrac{2}{3}\right)(-9)+14c=-8c+6+14c\\\\=c(-8+14)+6\\\\=6c+6

22. You are to evaluate the expression with x=2 two ways: as is, and after you simplify it by combining like terms.

<u>As is:</u>

-8x+5-2x-4+5x\\=-8(2)+5-2(2)-4+5(2)\\=-16+5-4-4+10\\=-9

<u>Simplified:</u>

-8x+5-2x-4+5x\\=x(-8-2+5)+(5-4)=-5x+1\\=-5(2)+1=-10+1\\=-9

I prefer simplifying the expression first. The number of calculations and chances for error are reduced.

23. It is convenient to check for equivalence after simplifying both expressions.

<u>First Expression:</u>

8x^2+3\left(x^2+y\right)=8x^2+3x^2+3y=11x^2+3y

<u>Second Expression:</u>

7x^2+7y +4x^2-4y=(7+4)x^2+(7-4)y=11x^2+3y

The simplified forms of the expressions are identical, so we conclude the expressions are equivalent.

25. The area of a rectangle is the product of its length and width. Here, you are asked to simplify the product of (3+x) ft and 3 ft.

((3+x)\,\text{ft})(3\,\text{ft})=(3\,\text{ft})\cdot (3\,\text{ft})+(x\,\text{ft})\cdot (3\,\text{ft})=9\,\text{ft}^2+3x\,\text{ft}^2\\\\=(3x+9)\,\text{ft}^2

In the last form of this expression, we have used "standard form" which has the degree of the variable decreasing in terms left to right. The units are factored out to make the expression a bit less cumbersome.

3 0
3 years ago
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