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azamat
3 years ago
7

A computer has 128 gigabytes of memory. One gigabyte is 1×10^9 9 bytes. By comparison, a floppy storage disk from the 1970's, ho

lds about 80 kilobytes. There are 1000 bytes in a kilobyte. How many kilobytes of memory does a modern computer have? Express your answer in scientific notation and as a decimal.
Mathematics
1 answer:
Blababa [14]3 years ago
6 0

Answer:

45

Step-by-step explanation:

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1,000 milliliters are in a liter. I hope I helped :)
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3 years ago
Three fair dice are rolled, one red, one green and one blue. What is the probability that the upturned faces of the three dice a
r-ruslan [8.4K]

Answer:   \dfrac{5}{9}

Step-by-step explanation:

When we throw a die , Total outcomes =6

When we throw 3 dice , Total outcomes = 6 x 6 x 6 = 216 [by fundamental counting principle]

Given : Three fair dice are rolled, one red, one green and one blue.

Favorable outcomes : When the upturned faces of the three dice are all of different numbers i.e. no repetition of numbers allowed

By Permutations , the number of favorable outcomes = ^6P_3=\dfrac{6!}{(6-3)!}=\dfrac{6!}{3!}=6\times5\times4=120

The probability that the upturned faces of the three dice are all of different numbers = \dfrac{\text{Favorable outcomes}}{\text{Total outcomes}}

=\dfrac{120}{216}=\dfrac{5}{9}

The probability that the upturned faces of the three dice are all of different numbers  is \dfrac{5}{9} .

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3 years ago
I need this question awnserd fast please help me.
EastWind [94]

Answer:

She started with 200 stamps

Step-by-step explanation:

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PLEASE HELP ASAP!! RATIONAL EXPRESSION MULTIPLE CHOICE QUESTION!! PLS
Solnce55 [7]
The answer is: B

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2 years ago
A genetics experiment involves a population of fruit flies consisting of 1 male named Bart and 3 females named Charlene, Diana,
kenny6666 [7]

Answer:

(b) \frac{1}{2}

Step-by-step explanation:

1 male named Bart (b)

3 females named Charlene(c), Diana(d), and Erin(e).

Since there is replacement, the possible samples are:

bb, bc, be, bd, cb, cc, cd, ce, db, dc, dd, de, eb, ec, ed, and ee.

Total Number of pairs = 16

Event of picking 2 males:bb

Event of 1 male:bc,cb,bd,db,be,eb

Event of picking 0 males:

cc, cd, ce, dc, dd, de, ec, ed, and ee.

\begin{equation*} \begin{matrix}Proportion of males & Probability \\0 & 9/16 \\1 & 6/16 \\2 & 1/16 \end{matrix} \end{equation*}

b. The mean of the sampling distribution

\mu = (\frac{9}{16} X0 ) +(\frac{6}{16} X 1)+(\frac{1}{16} X 2) = \frac{8}{16} = \frac{1}{2}

c.  No; the proportion of males is \frac{1}{4} while the mean is \frac{1}{2}.

B. No, the sample mean is not equal to the population proportion of males. These values are not always equal, because proportion is an unbiased estimator.

7 0
3 years ago
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