Answer:
0.09375 tons
Step-by-step explanation:
In this problem, it is given that Samuel has 3/4 tons of mulch i.e. 0.75 tons of mulch.
Again it is given that Samuel has to spread equally this amount of mulch in 8 square yards of the plot.
Since the mulch is spread uniformly, then we can say that in each square yard of the plot (0.75/8) = 0.09375 tons of mulch is been spread.
Therefore, 0.09375 tons of mulch will be spread in each square yard. (Answer)
Answer:
correct statements in Q no. 17 are;
Answers for Q no. 18;
Step-by-step explanation:
<span>The numbers of beads on 500 handcrafted bead necklaces follow a normal distribution whose mean is 24 beads and standard deviation is 4 beads.
</span>so....
<span>About 24 necklaces have more than 28 beads. </span>
<span>About 48 necklaces have more than 28 beads. </span>
<span>About 80 necklaces have more than 28 beads. </span>
About 96 necklaces have more than 28 beads<span>
</span> <span>About 80 necklaces have more than 28 beads.
</span><span>
Z score is 28-24/4=1
(1-.8413)=0.1587
500*0.1587=79.35~80
i did this like 2 or 3 years ago .</span>
Answer:
-9 = 0.45m
Step-by-step explanation:

- ^ Subtract 0.45m from BOTH sides. so
... etc - Why? So that we can make the equation less complicated. Our goal is to isolate the variable m to be on one side of the "=" sign by itself
- That will equal to:
<-- ANSWER
Answer:
- 892 lb (right)
- 653 lb (left)
Step-by-step explanation:
The weight is in equilibrium, so the net force on it is zero. If R and L represent the tensions in the Right and Left cables, respectively ...
Rcos(45°) +Lcos(75°) = 800
Rsin(45°) -Lsin(75°) = 0
Solving these equations by Cramer's Rule, we get ...
R = 800sin(75°)/(cos(75°)sin(45°) +cos(45°)sin(75°))
= 800sin(75°)/sin(120°) ≈ 892 . . . pounds
L = 800sin(45°)/sin(120°) ≈ 653 . . . pounds
The tension in the right cable is about 892 pounds; about 653 pounds in the left cable.
_____
This suggests a really simple generic solution. For angle α on the right and β on the left and weight w, the tensions (right, left) are ...
(right, left) = w/sin(α+β)×(sin(β), sin(α))