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svp [43]
3 years ago
13

A rectangular parking lot is surrounded on its perimeter by a fence that is 1200 feet long. if the length of a rectangular parki

ng lot is 5 times it’s width which equation can be used to find the width of the parking lot
Mathematics
2 answers:
r-ruslan [8.4K]3 years ago
8 0

Answer:

fah)',55%9+*_)64•%π\¥)--_f

AfilCa [17]3 years ago
4 0

Answer:

2w+2(w+5)=1200

Step-by-step explanation:

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What is 5/9 divided by 7/9
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4 years ago
A conical paper funnel of radius 4 and height 6 units is needed to make a good cup of coffee. If this funnel is made out of a se
Nimfa-mama [501]

Answer:

The radius of this circle is 2\sqrt{13} and the central angle of the sector is \theta=\frac{2}{\sqrt{13}}\times360^\circ.

Step-by-step explanation:

Consider the provided information.

If a conical paper funnel is made out of a sector of circle then the radius of the sector becomes the slant height of the cone, and the length of the curved part of the sector becomes the circumference of the base of the cone.

First find the slant height: l=\sqrt{r^2+h^2}

l=\sqrt{4^2+6^2}

l=\sqrt{16+36}

l=2\sqrt{13}

Thus, the radius of the sector is 2\sqrt{13} which is same as the slant height of the cone.

Now, the circumference of the base of the cone is same as the length of the curved part.

C=2\pi r

C=2\pi \times4=8\pi

The length of the curved part = \frac{\theta}{360\circ}\times2\pi r

\frac{\theta}{360\circ}\times2\pi \times2\sqrt{13}=8\pi

\frac{\theta}{360\circ}\times\sqrt{13}=2

\theta=\frac{2}{\sqrt{13}}\times360^\circ

Hence, the radius of this circle is 2\sqrt{13} and the central angle of the sector is \theta=\frac{2}{\sqrt{13}}\times360^\circ.

4 0
4 years ago
Select the correct answer from each drop-down menu. In the figure, . Angles are congruent . ∠GAC ≅ ∠AFE because they are corresp
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Answer:

∠GAC ≅ ∠HFD by the Property of Congruence.

Step-by-step explanation:

I'm going to be honest the question is a little confusing cause of the beginning, but if you're looking for which angles are actually congruent it's ∠GAC ≅ ∠HFD

8 0
3 years ago
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