Answer:
A. 45 + 42p
Step-by-step explanation:
Answer:
The critical value is ![T_{c} = 1.415](https://tex.z-dn.net/?f=T_%7Bc%7D%20%3D%201.415)
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 8 - 1 = 7
80% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 7 degrees of freedom(y-axis) and a confidence level of
. So we have T = 1.415.
The critical value is ![T_{c} = 1.415](https://tex.z-dn.net/?f=T_%7Bc%7D%20%3D%201.415)
The information about the coordinate plane shows that the slope of XV is 1.
<h3>How to illustrate the information?</h3>
From the information, the slopes of the diagonals are negative reciprocals. Therefore, the slope of UW is -1 and the slope of XV is 1.
The diagonals of kite UVWX are perpendicular.
It should be noted that negative reciprocals in a kite create a perpendicular bisector. So the two lines share a midpoint so they are perpendicular.
Learn more about coordinate plane on:
brainly.com/question/10737082
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The answer is
<span>−(x−1)(x+9)=0
</span><span>3x^2−6x=0
According to the zero product property:
If a * b = 0, then either a = 0 or b = 0
If </span>−(x−1)(x+9)=0, then either x - 1 = 0 or x + 9 = 0
<span>3x^2−6x=0 need to be written in factor form:
x(3x - 6) = 0
So if </span>x(3x - 6) = 0, ten either x = 0 or 3x - 6 = 0