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Harlamova29_29 [7]
3 years ago
15

PLZ HELP URGETLY!!!!!!!!Let u = 14. What is the value of 4u? A. 10 B. 18 C. 56 D. 144

Mathematics
1 answer:
Reptile [31]3 years ago
6 0
<span>Let u = 14. What is the value of 4u? 

</span><span>4(14) = 56
answer is </span><span>C. 56
</span><span>
Elliot wrote this expression to describe the total number of games he has left to play this season. 

g – 10 

Which situation could be described by this expression?

Answer


B. Elliot does not know the total number of games he has to play. He knows that he has played 10 games so far.


</span>
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In a home theater system, the probability that the video components need repair within 1 year is 0.02, the probability that the
earnstyle [38]

Answer:

(a) The probability that at least one of these components will need repair within 1 year is 0.0278.

(b) The probability that exactly one of these component will need repair within 1 year is 0.0277.

Step-by-step explanation:

Denote the events as follows:

<em>A</em> = video components need repair within 1 year

<em>B</em> = electronic components need repair within 1 year

<em>C</em> = audio components need repair within 1 year

The information provided is:

P (A) = 0.02

P (B) = 0.007

P (C) = 0.001

The events <em>A</em>, <em>B</em> and <em>C</em> are independent.

(a)

Compute the probability that at least one of these components will need repair within 1 year as follows:

P (At least 1 component needs repair)

= 1 - P (No component needs repair)

=1-P(A^{c}\cap B^{c}\cap C^{c})\\=1-[P(A^{c})\times P(B^{c})\times P(C^{c})]\\=1-[(1-0.02)\times (1-0.007)\times (1-0.001)]\\=1-0.97216686\\=0.02783314\\\approx 0.0278

Thus, the probability that at least one of these components will need repair within 1 year is 0.0278.

(b)

Compute the probability that exactly one of these component will need repair within 1 year as follows:

P (Exactly 1 component needs repair)

= P (A or B or C)

=P(A\cap B^{c}\cap C^{c})+P(A^{c}\cap B\cap C^{c})+P(A^{c}\cap B^{c}\cap C)\\=[0.02\times (1-0.007)\times (1-0.001)]+[(1-0.02)\times 0.007\times (1-0.001)]\\+[(1-0.02)\times (1-0.007)\times 0.001]\\=0.02766642\\\approx 0.0277

Thus, the probability that exactly one of these component will need repair within 1 year is 0.0277.

7 0
3 years ago
Solve using the substitution method. Show your work. If the system has no solution or an infinite number of solutions, state thi
vladimir2022 [97]
The answer is x = 10, y = 10.

Step 1: rearrange the second equation for y.
Step 2: substitute y from the second equation into the first equation.
Step 3. Calculate y.

Step 1.
<span>The second equation is: 6x + 3y = 90
Divide both sides of the equation by 3:
(6x + 3y)/3 = 90/3
6x/3 + 3y/3 = 30
2x + y = 30
Rearrange the equation:
y = 30 - 2x

Step 2.
</span>Substitute y from the second equation (y = 30 - 2x) into the first equation:
<span>15x + 9y = 240
15x + 9(30 - 2x) = 240
15x + 270 - 18x = 240
15x - 18x = 240 - 270
-3x = -30
x = -30/-3
x = 10

Step 3.
Since </span>y = 30 - 2x and x = 10, then:
y = 30 - 2 * 10
y = 30 - 20
y = 10
6 0
3 years ago
What is 7200 minutes in days
egoroff_w [7]
The answer would be 5 days in total
5 0
3 years ago
Shu Yi can't resist a sale. She recently bought a dress for $93 after it had been discounted 25%. She also purchased shoes that
faust18 [17]
First divide 93 by 3 to get 25% of the original price: 31. Then multiply it by 4 to get the whole original price, which is $124. Now onto the shoes. 
Divide 119 by 17 to get 7, which is 5% of the original price for the shoes. Then multiply 7 by 20, which is $140 for shoes. 
Subtract 124-93 to get 31, the savings on the dress and also subtract 
140-119 to get 21, savings on the shoes. Then add them together to get a grand savings total of $52 in savings. Hope this helps!
7 0
3 years ago
Solve 8-7x=22. Please show working out. thank you
Burka [1]
8-7x=22
Subtract 8 from both sides
-7x=14
Divide -7 on both sides
Final Answer: x=-2
7 0
3 years ago
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