1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Colt1911 [192]
2 years ago
6

What is the equation of a line that passes through the point (-1, 3) and is parallel to y=2x -7

Mathematics
1 answer:
natta225 [31]2 years ago
3 0
So because it’s parallel you’re gonna have the same slope. You need to use point slope formula to find the equation of the line

y-y1=m(x-x1). Here, x1= -1 and y1=3. Your m is the slope which is parallel which means you’re gonna have the same slope. Our equation is given in y=mx+b form so our m is 2 so the parallel slope is 2. So m=2, x1=-1, y1=3

Plugging all of these in you have

y-3=2(x-(-1))

Simplifying we have

y-3=2(x+1)

Applying distributive property we have

y-3=2x+2

adding 3 to each side we get

y=2x+5

Hope this helps!!!

You might be interested in
Part I - To help consumers assess the risks they are taking, the Food and Drug Administration (FDA) publishes the amount of nico
IRINA_888 [86]

Answer:

(I) 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

(II) No, since the value 28.4 does not fall in the 98% confidence interval.

Step-by-step explanation:

We are given that a new cigarette has recently been marketed.

The FDA tests on this cigarette gave a mean nicotine content of 27.3 milligrams and standard deviation of 2.8 milligrams for a sample of 9 cigarettes.

Firstly, the Pivotal quantity for 99% confidence interval for the population mean is given by;

                                  P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean nicotine content = 27.3 milligrams

            s = sample standard deviation = 2.8 milligrams

            n = sample of cigarettes = 9

            \mu = true mean nicotine content

<em>Here for constructing 99% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

<u>Part I</u> : So, 99% confidence interval for the population mean, \mu is ;

P(-3.355 < t_8 < 3.355) = 0.99  {As the critical value of t at 8 degree

                                      of freedom are -3.355 & 3.355 with P = 0.5%}  

P(-3.355 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 3.355) = 0.99

P( -3.355 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 3.355 \times {\frac{s}{\sqrt{n} } } ) = 0.99

P( \bar X-3.355 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+3.355 \times {\frac{s}{\sqrt{n} } } ) = 0.99

<u />

<u>99% confidence interval for</u> \mu = [ \bar X-3.355 \times {\frac{s}{\sqrt{n} } } , \bar X+3.355 \times {\frac{s}{\sqrt{n} } } ]

                                          = [ 27.3-3.355 \times {\frac{2.8}{\sqrt{9} } } , 27.3+3.355 \times {\frac{2.8}{\sqrt{9} } } ]

                                          = [27.3 \pm 3.131]

                                          = [24.169 mg , 30.431 mg]

Therefore, 99% confidence interval for the mean nicotine content of this brand of cigarette is [24.169 mg , 30.431 mg].

<u>Part II</u> : We are given that the FDA tests on this cigarette gave a mean nicotine content of 24.9 milligrams and standard deviation of 2.6 milligrams for a sample of n = 9 cigarettes.

The FDA claims that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette, and their stated reliability is 98%.

The Pivotal quantity for 98% confidence interval for the population mean is given by;

                                  P.Q. =  \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }  ~ t_n_-_1

where, \bar X = sample mean nicotine content = 24.9 milligrams

            s = sample standard deviation = 2.6 milligrams

            n = sample of cigarettes = 9

            \mu = true mean nicotine content

<em>Here for constructing 98% confidence interval we have used One-sample t test statistics as we don't know about population standard deviation.</em>

So, 98% confidence interval for the population mean, \mu is ;

P(-2.896 < t_8 < 2.896) = 0.98  {As the critical value of t at 8 degree

                                       of freedom are -2.896 & 2.896 with P = 1%}  

P(-2.896 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 2.896) = 0.98

P( -2.896 \times {\frac{s}{\sqrt{n} } } < {\bar X-\mu} < 2.896 \times {\frac{s}{\sqrt{n} } } ) = 0.98

P( \bar X-2.896 \times {\frac{s}{\sqrt{n} } } < \mu < \bar X+2.896 \times {\frac{s}{\sqrt{n} } } ) = 0.98

<u />

<u>98% confidence interval for</u> \mu = [ \bar X-2.896 \times {\frac{s}{\sqrt{n} } } , \bar X+2.896 \times {\frac{s}{\sqrt{n} } } ]

                                          = [ 24.9-2.896 \times {\frac{2.6}{\sqrt{9} } } , 24.9+2.896 \times {\frac{2.6}{\sqrt{9} } } ]

                                          = [22.4 mg , 27.4 mg]

Therefore, 98% confidence interval for the mean nicotine content of this brand of cigarette is [22.4 mg , 27.4 mg].

No, we don't agree on the claim of FDA that the mean nicotine content exceeds 28.4 milligrams for this brand of cigarette because as we can see in the above confidence interval that the value 28.4 does not fall in the 98% confidence interval.

5 0
2 years ago
2x 2 + 10-12<br> X +6<br> Simplify
jenyasd209 [6]

Answer:

-72 X + 14

Step-by-step explanation:

6 0
3 years ago
Which of the following is(are) true? I. The mean of a population depends on the particular sample chosen. II. The standard devia
Margarita [4]

Answer:

II and III

Step-by-step explanation:

From statement II in the question, it is true that the standard deviations of two different samples from the same population may be the same. The population standard deviation is a fixed value calculated from every individual in the population.  A sample standard deviation is calculated from only some of the individuals in a population.

Also from statement III, it is true that statistical inferences can be used to draw conclusions about the populations based on sample data. The mean of a population does not necessarily depends on the particular sample chosen. Therefore statement I is false.  

3 0
3 years ago
PLEASE HELP<br> ILL GIVE U BRAINLEIST<br> AND 5 STARS:)
skad [1K]

Answer:

The slope is undefined!!but DONTTTT trust my answer if you are in exam or test

5 0
2 years ago
Read 2 more answers
Which graph represents the function?<br><br> f(x)=−x2+x+6
sergiy2304 [10]
First page , second image is the correct answer :)
4 0
3 years ago
Other questions:
  • -4<br><img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B16x8%20%3D%20%7D%20" id="TexFormula1" title=" \sqrt{16x8 = } " alt=" \sqrt{
    13·1 answer
  • What are the x-intercepts of the quadratic function y=x^2-x-2
    12·2 answers
  • One positive number is 4 more than twice another. Their product is 198
    6·2 answers
  • Need help here guys.
    13·1 answer
  • What’s the product of(-3.4)(5)
    5·1 answer
  • C. What is f (-5)?<br> When the function is f(x) =-3x+7
    11·1 answer
  • The prime factorization of 16x5
    14·1 answer
  • Find the length of the hypotenuse
    7·2 answers
  • 5. From 13 friends to 14 friends
    8·1 answer
  • What is the scale factor from ABC to DEF?<br> A. 2<br> B. 1/2<br> C. 3<br> D. 1/3
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!