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3 years ago

Find each product or quotient. 16 ÷ (-8) = P.S its not -2

1 answer:

Elena-2011 [213]3 years ago

8 0

I got -0.5 if you divide it like this 16 divided by (-8) you will get -2 but if you flip them you get 0.5. If you need more help on stuff like this then you can always use desmos | scientific calculator

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25 points! Please help!

Annette [7]

Answer: 15 minutes

Explanation:

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3 years ago

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A new soup recipe contains 33\%33%33, percent less sodium per serving than the old soup recipe. The old soup recipe contained xx

Mashcka [7]

Answer:

0.67x mg

Step-by-step explanation:

expression that could represent the amount of sodium per serving, in milligrams, in the new soup recipe

33% less than the old

old contains x mg

new soup: x - 33%x = x - 33/100x = x - 0.33x = 0.67x mg

67%x mg

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3 years ago

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Virty [35]

Answer:

2438.4

Step-by-step explanation:

multiply 96 by 25.4

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3 years ago

Using 5,7,2 to equal 6

choli [55]

Answer:

here my answer

Step-by-step explanation:

5+1=6

7-1=6

3x2=6

hope it helps :)

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3 years ago

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2. The Welcher Adult Intelligence Test Scale is composed of a number of subtests. On one subtest, the raw scores have a mean of

IgorC [24]

Answer:

a) 37.31 b) 42.70 c) 0.57 d) 0.09

Step-by-step explaanation:

We are regarding a normal distribution with a mean of 35 and a standard deviation of 6, i.e., $\mu$ = 35 and $\sigma$ = 6. We know that the probability density function for a normal distribution with a mean of $\mu$ and a standard deviation of $\sigma$ is given by

$f(x) = \frac{1}{\sqrt{2\pi}\sigma}\exp[-\frac{(x-\mu)^{2}}{2\sigma^{2}}]$

in this case we have

$f(x) = \frac{1}{\sqrt{2\pi}6}\exp[-\frac{(x-35)^{2}}{2(6^{2})}]$

Let $X$ be the random variable that represents a row score, we find the values we are seeking in the following way

a) we are looking for a number $x_{0}$ such that

$P(X\leq x_{0})$ = $\int\limits^{x_{0}}_{-\infty} {f(x)} \, dx = 0.65$ , this number is $x_{0}$ =37.31

you can find this answer using the R statistical programming languange and the instruction qnorm(0.65, mean = 35, sd = 6)

b) we are looking for a number $x_{1}$ such that

$P(X\leq x_{1})$ = $\int\limits^{x_{1}}_{-\infty} {f(x)} \, dx = 0.9$ , this number is $x_{1}$ =42.70

you can find this answer using the R statistical programming languange and the instruction qnorm(0.9, mean = 35, sd = 6)

c) we find this probability as

$P(28\leq X\leq 38)$ = $\int\limits^{38}_{28} {f(x)} \, dx = 0.57$

you can find this answer using the R statistical programming languange and the instruction pnorm(38, mean = 35, sd = 6) -pnorm(28, mean = 35, sd = 6)

d) we find this probability as

$P(41\leq X\leq 44)$ = $\int\limits^{44}_{41} {f(x)} \, dx = 0.09$

you can find this answer using the R statistical programming languange and the instruction pnorm(44, mean = 35, sd = 6) -pnorm(41, mean = 35, sd = 6)

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4 years ago

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