Answer:
(i)unique solution
Explanation:
We solve for x1 thus in the first equation:
x1-3x3=-3
x1-9=-3
x1=-3+9
x1= 6
We solve for a thus in the second equation:
2x1+ax2-x3=-2
2+a2-x3=-2
a2-x3=-4
a2=-4+x3
Answer:
If pi is used as pi 113.1
or
If 3.14 is used as pi 113.04
Step-by-step explanation:
A = pi(r)²
<span>The expression:
2-². 2² + 2 (3²) ² + 18 / 8² / ³
it's the same as:
0BS. the number 2 the start of expression is elevated to -2 and the whole expression is being divided by 8 2/3 high.</span>
