The vertical asympototes of f(x) are at x = -6 and x = 6
Step-by-step explanation:
To find the vertical asymptote(s) of a rational function,
- Equate the denominator by 0
- Solve it for x
- If x = a, then the vertical asymptote is at x = a
∵ ![f(x)=\frac{4x^{2}+3x+6}{x^{2}-36}](https://tex.z-dn.net/?f=f%28x%29%3D%5Cfrac%7B4x%5E%7B2%7D%2B3x%2B6%7D%7Bx%5E%7B2%7D-36%7D)
- Equate the denominator x² - 36 by 0
∵ x² - 36 = 0
- Add 36 to both sides
∴ x² = 36
- Take √ for both sides
∴ x = ± 6
∴ There are vertical asymptotes at x = -6 and x = 6
The vertical asympototes of f(x) are at x = -6 and x = 6
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Answer:
I think the answer is A
8x³y⁴ ³squareroot xy
Step-by-step explanation:
Mark as brainllest if it helps!!!
Answer:
The required y-value is -121.
Step-by-step explanation:
There are several ways in which we could approach this problem. From the two binomial factors (x + 8) and (x - 14), we know that the two roots are x = -8 and x = 14. The axis of symmetry is the vertical line x = 3. This value is halfway between x = -8 and x = 14.
Substituting x = 3 into f(x)= -(x+8)(x-14) results in f(3) = -(11)(-11) = -121.
The vertex is at (3, -121). The required y-value is -121.
Answer: I think it’s A
Step-by-step explanation:
But go for it