Question

What are the solutions to the quadratic equation (round to nearest hundredth) x2 + 6x -6 = 0 ?

Answer 1

Answer:

x = 0.88 OR x = -6.88

Step-by-step explanation:

Given the quadratic equation: $x^{2}$ + 6x - 6 = 0

Applying the quadratic formula to determine the solutions, we have:

x = (-b ± $\sqrt{b^{2} - 4ac}$) / 2a

where; a = 1, b = 6 and c = -6

x = ( -6 ± $\sqrt{6^{2} -4 (1 * -6) }$) / 2

  = ( -6 ± $\sqrt{36 + 24}$) / 2

  = (-6 ± $\sqrt{60}$) / 2

x = (-6 ± 7.75) / 2

So that,

x = (-6 + 7.75) / 2 OR x = (-6 - 7.75) / 2

x = $\frac{1.75}{2}$ OR $\frac{-13.75}{2}$

x = 0.88 OR -6.88

Thus, the solutions are: x = 0.88 OR x = -6.88