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telo118 [61]
3 years ago
7

If the function f has a continuous derivative on [0,c], the the integral(o to

Mathematics
1 answer:
vaieri [72.5K]3 years ago
4 0
For the first problem,
The definite integral from 0 to c is
[f(c) - f(0)] / (c - 0)
since the function is continuous in the interval 0 to c.

Since f(a) = f(b) = 1, then by the Mean Value Theorem, there is a point somewhere in the middle two values of x that f'(x) = 0 since the curve has a degree of more than 2.
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Find the value of x (URGENT/GIVING BRAINLIEST)
natta225 [31]

Answer:

B)10

Step-by-step explanation:

Because this is a right angle(indicated by the red box) the total measure should be 90°.

And based on that we say 5X +40=90

Subtract 40 from both sides to get 5x=50

And then divide both sides by 5 to get x=10

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2 years ago
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Cos(5 π/3)=___<br><br> A. √3/2<br> B. -√2/2<br> C. 1/2<br> D. √2/2
Ratling [72]

Answer:

i think the answer is C. 1/2

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2 years ago
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ANTONII [103]

Answer:

19 orders of tea

57 orders of collee

Step-by-step explanation:

find 1/4 of the 76

76/4=19

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8 0
3 years ago
Use the drawing tool(s) to form the correct answer on the provided graph.
Dominik [7]

Answer:

  see below. The solution is the doubly-shaded area.

Step-by-step explanation:

Each boundary line will be dashed, because the "or equal to" case is <em>not included</em>. Each shaded area will be above the corresponding boundary line because the comparison symbol is y > .... That is, only y-values greater than (above) those in the boundary line are part of the solution.

Of course, the boundary lines are graphed in the usual way. Each crosses the y-axis at the value of the constant in its equation. Each has a slope (rise/run) that is the value of the x-coefficient in the equation.

3 0
3 years ago
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Find the volume of the compound shape.​
jeyben [28]
<h3>Given:</h3>
  • Hemisphere ×2 or sphere
  • Cylinder
<h3>Solution:</h3><h3>Volume of the sphere:</h3>

v =  \frac{4}{3}  \pi {r}^{3}

v =  \frac{4}{3}  \times \pi \times  {2}^{3}

v = 33.51 \:  {m}^{3}

<h3>Volume of the cylinder:</h3>

v = \pi {r}^{2} h

v = \pi \times  {2}^{2}  \times 6

v = 75.40 \:  {m}^{3}

<h3>Total volume:</h3>

v = 75.40 + 33.51

v = 108.91 \:  {m}^{3}

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>compound</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>108.91</u><u> </u><u>cubic</u><u> </u><u>meters</u><u>.</u>

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1 year ago
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