Question

Two vectors m and n are defined by 3i+4j and n=2i-j. find the angle between m and n​

Answer 1

Answer:

${ \tt{m.n = |m| |n| \cos( \theta) }} \\ { \tt{ (3 \times 2) + (4 \times - 1) = (5)( \sqrt{5}) \cos( \theta) }} \\ { \tt{ \cos( \theta) = \frac{0.4}{ \sqrt{5} } }} \\ \theta = 79.7 \degree$

Answer 2

Answer:

$m.n=∣m∣∣n∣cos(θ)(3×2)+(4×−1)=(5)(5)cos(θ)cos(θ)=50.4θ=79.7°$

Step-by-step explanation:

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